Based on the LSE estimates in Question 10, generate an ANOVA table by using SSE 0.0447. Determine which factorial effects are significant at a = =0.05. %3D
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![Suppose a first order model without interaction is used for this experimentation, i.e.,
y = Bo + B1I1 + B212 + B3I3 + e. After applying LSE, we have
B = [Bo B1 B2 Bs]" = [14.1863 -0.0388 0.1188 -0.0313"
What are the factorial effects, ME(A), ME(B), and ME(C)?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd3485572-fbb4-4e09-a804-52fda58def39%2Fef43fc19-126c-4480-8b53-6a216c926fdc%2Fkuu8om_processed.jpeg&w=3840&q=75)
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- Explain the differences between Gaussian elimination and Gauss-Jordan elimination.What is the significance of R and R2 in gression model?Let B₁ and 3₂ denote the OLS estimators of B₁ and 2 in the regression: yi= Bo + Bixi + B2x₁2 + Ui. Let B₁ denote the OLS estimators of B₁ in the regression Vi = Bo + Bixil + Vi. Let 8₁=1(x₁ - x₁)(X₁2 - X₂) / Σ²-₁(x₁₁ — X₁)². a) ₁ is the OLS estimator of a slope parameter from what regression model? b) Show that 1(Vi-Bo - B₁x₁₁ - B2x₁2) (Xi1 — x₁) = 0. c) Prove that B₁ =B1 + Ổ₁ß2. Explain the situations in which omitting x2 from the model will NOT bias the OLS estimate of B₁.
- Can you please explain how to solve part i, using both the empirical rule and using a Z table?Consider the model Y = B1 + B2X + e, which we estimate using a random sample with 12 observations. Let bj and b2 be the estimators for B1 and B2 and recall Eê, where ê; = Y; – bị – b2X;. Suppose the sample correlation between {X; }"_-1 and {Y;}"_, is 0.5 and E(Y; – Ỹ„)² = 100. What is ổ?? %3D n-2 Hint: (i) for simple regression, the regression R? is equal to the squared sample correlation between X and Y. (ii) R² = 1 – SSE where SSE = Eế and SST SST = O a. 7.5 O b. 8.5 О с. 9 O d. 10 O e. 8 O f. 7 Clear my choiceExplain the Stationarity in the AR(1) Model?
- 3) A medical association claims that less than 20% of adults in the US are regular smokers of tobacco. To test this claim the survey a sample of 125 US adults and find that 19 of them are regular smokers. Test the medical association's claim using α=0.05.Lin Chi-Ling works for an insurance company and is studying the relationship between types of crashes and the vehicles involved in passenger vehicle occupant deaths. As part of your study, you randomly select 4270 vehicle crashes and organize the resulting data as shown in the contingency table. At α = 0.05 can you conclude that the type of crash depends on the type of vehicle? Vehicle Type of crash Car Pickup Sport utility Single-vehicle 1237 547 479 Multiple-vehicle 1453 307 247 What is the Chi-square test statistics and the decision for this question. The Test statistics is . Leave answers in 3 decimal places. DECISION: We the null hypothesis.In an experimental study, it was noticed that people who eat more leafy, green vegetables tend to get better sleep than the general population. Researchers wonder whether the improved sleep might be caused by the minerals potassium and magnesium found in leafy, green vegetables. How could the researchers design an experiment to determine the effects of potassium and magnesium on sleep?
- A cream with alpha-hydroxy acid, advertises that it can reduce wrinkles and improve the skin. In a study published in Archives of Dermatology (June 1996), 49 middle-aged women used a cream with alpha-hydroxy acid for 22 weeks. At the end of the study period, a dermatologist judged whether each woman exhibited any improvement in the condition of her skin. The results for the 49 women (where I = improved skin and N = no improvement) were: 32 I’s and 17 N’s. (a) Find a 95% confidence interval for p, the true population proportion of middle-aged women with improved skin after using this cream. Interpret the interval. (b) What assumptions are required for the confidence interval of part (a) to be statistically valid? (c) Are the assumptions for part (b) reasonably satisfied? Explain.A researcher wants to find the effect of a special diet on systolic blood pressure. A sample of 7 adults was selected to start them on this diet for 3 months. Based on this information, can it be stated that systolic blood pressure changes with the special diet? Based on the findings of the test carried out, it is possible to conclude that...... A. systolic blood pressure does not change with special diet B. systolic blood pressure changes with special diet C. systolic blood pressure is lower with the special diet D. systolic blood pressure is higher with the special diet E. It is not possible to conclude anything regarding systolic blood pressure with the special dietPatients diagnosed with retinopathy (disease of the retina) were admitted into a study where they were randomly assigned to one of the two treatments and monitored for 6 years. The study found that 143 of the 352 patients assigned to the conventional treatment (group 1) showed an improvement of their disease. Whereas 177 of the 363 patients assigned to the intensive treatment (group 2) had improvement of the disease. Suppose you are hypothesizing that the intensive treatment (Group 2) is more effective than the conventional treatment (Group 1) but hypotheses are written in the form of Group 1-Group 2. Conducting a test of significance (at a 5%) with the hypotheses you chose from Question 9, you calculated a p-value equal to which made you decide to O A) 0.9861; fail to reject Ho B) 2.20; fail to reject Ho OC) 0.0139; reject Ho D) 0.0139; fail to reject Ho E) -2.20; reject Ho
