2. : Clearly STATE your NULL hypothesis. 3. Choose one 'group' results (for example you may choose group 4 from cross 2), complete the Chi-square Analysis with ONLY that group's data. Fill in the table below to help you determine the statistical significance of your chi-square. (you'll need to make multiple copies of this table, and may need to add more rows) Expected Cross Observed Expected (E) O-E (O-E)? (O-E)/E (0) Ratio Sum of (O-E)?/IE: 4. The "sum of (O-E)?/E" is the X? value. X2 = 5. Determine the degrees of freedom and probability using the chi-square distribution chart (see last page). 6. Repeat the chi square analysis on the TOTAL data for that cross. (Essentially you're doing chi-square tests twice for each cross, once with one group, another time with the total data from all groups) Review your data and hypothesis. You have assumed that chance (and chance only) has been operating in the independent assortment of alleles that gave rise to the F1 and F2 you investigated. Thus, any variation of your observed results as recorded above from the expected results is due to chance. This is known as the "null hypothesis." Cross s 6 total 3. Wild type 20 12 Ebory Vestig al 27 23 25 60 167 3 7 9 40 10 3 3 12 42 316 11

2. : Clearly STATE your NULL hypothesis. 3. Choose one 'group' results (for example you may choose group 4 from cross 2), complete the Chi-square Analysis with ONLY that group's data. Fill in the table below to help you determine the statistical significance of your chi-square. (you'll need to make multiple copies of this table, and may need to add more rows) Expected Cross Observed Expected (E) O-E (O-E)? (O-E)/E (0) Ratio Sum of (O-E)?/IE: 4. The "sum of (O-E)?/E" is the X? value. X2 = 5. Determine the degrees of freedom and probability using the chi-square distribution chart (see last page). 6. Repeat the chi square analysis on the TOTAL data for that cross. (Essentially you're doing chi-square tests twice for each cross, once with one group, another time with the total data from all groups) Review your data and hypothesis. You have assumed that chance (and chance only) has been operating in the independent assortment of alleles that gave rise to the F1 and F2 you investigated. Thus, any variation of your observed results as recorded above from the expected results is due to chance. This is known as the "null hypothesis." Cross s 6 total 3. Wild type 20 12 Ebory Vestig al 27 23 25 60 167 3 7 9 40 10 3 3 12 42 316 11

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter13: Patterns In Inherited Traits

Section: Chapter Questions

Problem 6GP: In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele...

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