If you analyze a double-stranded DNA molecule and find that 15% of all the nucleotide bases areAdenines, you know that there must also be [ Select ]Thymines,[ Select ]Guanines, [ Select ]v Cytosines and[ Select ]Uracils. (Count each of the bases in any double stranded DNA moleculeand calculate their percentages to find the simple key for this if you haven't seen it yet.)

According to Chargaff's rule, [A]+[G]=[C]+[T] where A - adenine G - Guanine C- Cytosine T- Thymine

Answered: If you analyze a double-stranded DNA…

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 14QP: How many kilobases of the DNA strand below will code for the protein product?

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How many possible nucleotide sequences are there for a stretch of DNA that is N nucleotides long, if it is (a) single- stranded or (b) double-stranded?
Amino acids have an average molar mass of 100 g/mol.How many bases on a single strand of DNA are needed to codefor a protein with a molar mass of 5x10^5g/mol?
Given the following eukaryotic DNA strand, transcribe and translate the DNA into a polypeptide using the 3’ – 5’ strand as the template. You may use drawings, diagrams, colours and annotations to describe how the DNA strand will be synthesized into a functional protein. (32) (KEY: The letters SBMD are “made up” nucleic acids that depict non-coding regions in the DNA, hypothetically S pairs with B and M pairs with D). 5’ - TATAAAAASSMSBMDATGSBDCCMBDBAATBSMDSTGTGTCCTMSBAG – 3’
Permutation is the ordered arrangement of m number items out of a list of n items. For instance, the DNA strand with sequence of 3 bases: G-A-C IS different w ith A-G-C, C-A-G, G-C-A, A-C-G, and C-G-A. From this, we have: P-3) 3! 3x2x1 Therefore, there are 6 dıfferent sequences of DNA strands that can be formed out of 3 given bases. In general, we have this formula for permutation: (n-m)! Count the number of ways in which: Guanıne, Adenine, Cytosine, Thymıne, Cytosine, and Guanıne (6 bases) be sequenced in one DNA strand?
The composition (in molefraction units) of one of the strands of a double-helical DNA molecule is [A] = 0.30 and [G] =0.24. (a) What can you say about [T] and [C] for the same strand? (b) What can you say about [A], [G], [T], and [C] of the complementary strand?
The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine. The figure (Figure 1) shows the thymine-adenine bond. Each charge shown is ±e, and the H−N distance is 0.110 nm . Calculate the net force that thymine exerts on adenine. To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O−H−N and the N−H−N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O−H−N set, the O− exerts a force on both the H+ and the N−, and likewise along the N−H−N set. Express your answer in newtons. Is the net force attractive or repulsive?
The complementary strands of DNA in the double helixare held together by hydrogen bonds: G ≡ C or A = T.These bonds can be broken (denatured) in aqueous solutions by heating to yield two single strands of DNA(see Figure 1-13a). How would you expect the relativeamounts of GC versus AT base pairs in a DNA doublehelix to affect the amount of heat required to denatureit? How would you expect the length of a DNA doublehelix in base pairs to affect the amount of heat requiredto denature it?
Write the sequence of the complementary DNA strand thatpairs with each of the following DNA base sequences:(a) GGTTAC(b) CCCGAA
DNA structure depends on base pairing of its four nucleotides, A, C, T, and G. Nucleotide A pairs with T, and nucleotide C pairs with G. This forms a four-letter DNA “alphabet." Because DNA codes for amino acids in sets of three nucleotides, there are 4 cubed (4'), or 64, possible combinations, coding for 20 different amino acids. What is the best explanation for why there is no selective advantage for DNA to have five nucleotides (e.g., A, C, T, G, and E) with C pairing with either G or functionally equivalent E? It would be impossible to form the DNA molecule, because it must have an equal number of Cs and Gs. Because G and E have the same role, there would still be four functional letters of the alphabet. Replication would be inaccurate because sometimes C would bond with G and sometimes C would bond with E. There would be a five-letter alphabet with 125 combinations, which is too numerous. It is impossible because there are not five known nucleotides in the cell.
The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine. The figure below shows the bonding of thymine and adenine. Each charge shown is +e or - e, and the H-N distance is 0.110 nm. (a) Calculate the net force that thymine exerts on adenine. Is it attractive or repulsive? To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O- H-N and the N-H-N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O-H-N set, the O- exerts a force on both the H+ and the N-, and likewise along the N–H-N set. (b) Calculate the force on the electron in the hydrogen atom, which is 0.0529 nm from the proton. Then compare the strength of the bonding force of the electron in hydrogen with the bonding force of the adenine-thymine molecules (H (H (H)…
The length of a DNA molecule is 680 nm when the DNA molecule is in B-conformation. How many helical turns does the DNA molecule have if the DNA molecule is in A-conformation?
if this DNA has a molecular weight of 1.20 ×108 Dalton which contains a head in a about 200 nm long. Calculate the length of the DNA assuming the molecular weight of a nucleotide pair is 600 Dalton and assume that the DNA is a B-form and that there are 10 base pair per turn which makes is 34 Å per turn. ( 1nm = 10Å)

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