Bowling Ball Collision A bowling ball with a mass of mb moving at a speed of ы hits a pin with a mass of mp which is at rest. After the 1-D collision, the ball's speed has slowed to voƒ and the pin is moving at a speed of Upf. Ignore friction and air resistance. 6 ть Ubi mp Ubf Upf 6.39 8.94. m 1.64 5.89. m m kg S kg S S (no answer) Correct Answer: 11.9

College Physics
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ISBN:9781285737027
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Chapter6: Momentum And Collisions
Section: Chapter Questions
Problem 3P: A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-kg bullet moving...
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Bowling Ball Collision
A bowling ball with a mass of mb
moving at a speed of vыi hits a pin
with a mass of m₂ which is at rest.
After the 1-D collision, the ball's
speed has slowed to bf and the pin
is moving at a speed of Upf. Ignore
friction and air resistance.
6
ть
Ubi
mp
vbf
Upf
6.39
1.64
m
8.943
5.89
m
kg
S
kg
S
S
Х
(no answer)
Correct Answer: 11.9
Transcribed Image Text:Bowling Ball Collision A bowling ball with a mass of mb moving at a speed of vыi hits a pin with a mass of m₂ which is at rest. After the 1-D collision, the ball's speed has slowed to bf and the pin is moving at a speed of Upf. Ignore friction and air resistance. 6 ть Ubi mp vbf Upf 6.39 1.64 m 8.943 5.89 m kg S kg S S Х (no answer) Correct Answer: 11.9
Solution:
Conservation of Momentum for 1-D
collision:
m1v1i+m2 V2i = m1v1f + m2 v2f
Plug in (using Vpi
=
0):
mbvbi = mb V b f
mbvbf mpvpf
Transcribed Image Text:Solution: Conservation of Momentum for 1-D collision: m1v1i+m2 V2i = m1v1f + m2 v2f Plug in (using Vpi = 0): mbvbi = mb V b f mbvbf mpvpf
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