(c) The elevator decelerates at a rate of 0.35 8² (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. for 2.75 s. ΣF₁=T-m₂g= x mea (ii) Calculate the tension in the cable supporting the elevator. T= N (iii) How high has the elevator moved during this time? Ay= (d) What is the total distance the elevator has moved up? Ay net m m

(c) The elevator decelerates at a rate of 0.35 8² (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. for 2.75 s. ΣF₁=T-m₂g= x mea (ii) Calculate the tension in the cable supporting the elevator. T= N (iii) How high has the elevator moved during this time? Ay= (d) What is the total distance the elevator has moved up? Ay net m m

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 60P: Suppose Kevin, a 60.0-kg gymnast, climbs a rope. (a) What Is the tension in the rope if he climbs at...

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Suppose Kevin, a 60.0-kg gymnast, climbs a rope. (a) What Is the tension in the rope if he climbs at a constant speed? (b) What is the tension in the rope if he accelerates upward at a rate of 1.50m/s2 ?
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