c. void squire (int n) { if( n <= 1 ) time++; else { squire (n/2); squire (n/2); for (int i=0; i

Computer Networking: A Top-Down Approach (7th Edition)
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Chapter1: Computer Networks And The Internet
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I need help finding the Run Time Analysis of these code(s): Provide the tightest big-Oh bound on the run time for each of the following methods. Please explain how you got the answer and why it is case.  Master Theroum applicable here? Please explain in detail. 

c.
void squire (int n)
{
if( n <= 1 )
time++;
else
{
squire (n/2);
squire (n/2);
for (int i=0; i<n; i++)
for (int j=i; j<n; j++)
time++;
squire (n/2);
squire (n/2);
squire (n/2);
squire (n/2);
squire (n/2);
squire (n/2);
}
}
Transcribed Image Text:c. void squire (int n) { if( n <= 1 ) time++; else { squire (n/2); squire (n/2); for (int i=0; i<n; i++) for (int j=i; j<n; j++) time++; squire (n/2); squire (n/2); squire (n/2); squire (n/2); squire (n/2); squire (n/2); } }
Expert Solution
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complexity for loop inside else part is calculated then recurrance relation is framed and then calculation is done using master theorem

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