Calculate delta H for the reaction : Ch4+ 3Cl2= CHCl3+ 3HCl given: CH4 =-74.85(kJ/mol) HCl= -92.30(kJ/mol) CHCl3=-134.3 (kJ/mol) CHCl3=-103.2 (kJ/mol)

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Calculate delta H for the reaction : Ch4+ 3Cl2= CHCl3+ 3HCl

given: CH4 =-74.85(kJ/mol)

HCl= -92.30(kJ/mol)

CHCl3=-134.3 (kJ/mol)

CHCl3=-103.2 (kJ/mol)

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