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- 25.0 cm³ sodium hydroxide is neutralized by 15.0 cm³ sulphuric acid of concentration 0.10 mol dm-3. a. Write the equation for the reaction b. From the equation, determine how many moles of sulphuric acid will neutralize 1.0 mol of sodium hydroxide. c. Determine how many moles of sulphuric acid are used in the neutralization. d. Determine the concentration of sodium hydroxide.Write the expression for the K₂ when HC₂H3O₂ is dissolved in water HC₂H30₂ + H₂O C₂H30₂¹1 + H30+1 ][ Ka [ a. acetic g. sulfurous n. HPO4² u. H₂O [ b. hydrochloric h. hydrosulfuric o. H₂PO4¹ P. CO₂-² -3 v. H₂CO3 W. PO4³ c. phosphoric i. OH-1 ] d. perchloric j. H30+¹ k. SO4² q. HCO3-1 X. HC2H3O2 r. H₂S y. C₂H30₂-1 e. hydrofluoric 1. Mg+2 s. HS-1 t. S-² f. sulfuric m. Cl-12. Ni(P(0-C6H4Me)3)2Cl2 is strongly paramagnetic, while Ni(PMe3)2Cl2 is diamagnetic (see the structures - note that they are not shown with any three dimensional notation). Suggest a possible explanation, and show how it is compatible with their different magnetic properties. -Ph -P Ph Ph Ph Ph Ph .Ni CI CI P Ni CI CI
- d. [CH3CO,C,H5] = 4.4 M, [H20] = 4.4 M, [CHCO,H = 0.88 M, (C,H,OH = 10.0 M O increase O decrease O remain the same e. What must the concentration of water be for a mixture with (CH, CO, C,H;] = 1.0 M, JOCH CO,H = 0.10 M, and [C2H;OH] = 7.0 M to be atequilibrium? Concentration: MNH resulting from wH- Cl needed to provent Mgl oH)2 From precipitating in alite of a solution contaning o.o2mol of ammonia and o.odlnol From Mg- knuwing that the ionization canstant of ammania is 1-8 x1o and its solubititg mgloH)h 2112X10 の1.5X20 2.6*10M -2 O 2.5 X10 M -3 @1.6x10M HO o ab -2 ①1イメごm HOWhich of the following salts has the least molar solubility in water? Select one: O a. Fes (Ksp = 4 x 10-19) O b. PtS (Ksp 8 x 10-73) O c. NIS (Ksp = 8 x 10-37) O d. MnS (Ksp = 8 x 1016) O e. comparative solubility cannot be determined since molar masses are not given.
- 10. A 0.514 gram sample of NazCO, (106.0 g/mol) was dissolved in distilled water in a 100.0 mi volumetric flask. The molar concentration of Na,CO, in solution is: 0.0485 M 0.0370 M b. 0.4849 M 0.0340 M 0.0330 M d. е.If 2 ml of 25 N H2SO4 is transferred to 50 ml volumetric flask and complete to mark with ditilled water, the concentration of acid will be .. M* O 2.5 O 1.5 2 O 0.5 0 1 Non of theseCalculate the percent lonization. of acetic acid in a solution that is 0.2014 in acid (HC₂H30₂) and 0.20m z Oz in potassium actate (KC z H z O ₂ ) z The acid dissociation constant of acetic acid is 1.8x10-5. 0 5.6% 0.000912 0 0.38% O 12% 0.0 27%
- A 0.9182 g sample of CaBr2 is dissolved in enough water to give 500. mL of solution. What is the bromide ion concentration in this solution? 20 Multiple Cholce X 0206:02 9.19 x 10-3 M 230 x 10-2 M 272 x 10-3 M 1.84 x 10-2 M 1.25 x 10-1 M Mc Graw Hill Type here to search 近 C2. Explain why the observed color change with bromcresol green for each of the four solutions is reasonable given the pH. a. NaC.pH=7 b. Na;CO, pH =10.8 c. NaC;H,O, .pH-8.9 d. NaHSO.pH-1.5 Part C: 1. What was the unknown weak acid? From your observed pH calculate the [H+] concentration in M(mols/L) for your unknown acid 2. Calculate the Ka for the unknown acidi li. In. 3 ۱ ۱:۳۸ 88 EXPERIMENT A- preparation of approximately (0.1N) HCL B- preparation of (0.1N) Sodium carbonate Na2CO3 The aim of the experimental:- -help the student know how to prepare solution. -to know the techniques involves of standardization solution. - determine the concentration of an unknown solution( HCI ). A- preparation of approximately (0.1N) HCL 1. Calculate the normality of the concentrated HCL. Sp.g • Percentage • 1000 N= القانون الخاص بتحضير المحاليل السائلة equival ent wei ght equivalent weight = Molecular weight / no. of Hydrogen Sp.gr = 1.19 gm/em Percentage = 37 % (35.5 + 1) = 36.5 eq.wt (HCl) = H=1 Cl=35.5 N- 1.19- (37/100) × 1000 =12.0630 36.5 2-To prepare (500ML) of 0.1N HCI N¡ × Vị N2 × V2 conc.HOCI dil.HCl 12.0630 × Vị = 500 × 0.1 Vj= 4.1449 mL B- preparation of (0.1N) Sodium carbonate Na2cO3 Weight 1000 القانون الخاص لتحضير المواد الصلبة equivalent weight Volume(mL ) M. mass (23x2)+12+(16x3) 106 aCO;) = total charge for positive ion = 53 2 II >