Calculate the effective mass m* of electron with the momentum k- G/2 in a weak periodic potential U(r) = 2U0 cos(27x/a) for which the energy spectrum E(k) is given by Eq. (1.3.22) of Lect. 4. The mass m* is defined by the behavior of E(k) at k x G/2: h?q? E(k) = Em - G G 2m* Can m* be smaller or larger than the free electron mass?

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Calculate the effective mass m* of electron with the momentum
k G/2 in a weak periodic potential U(x) = 2Uo cos(27x/a) for which the
energy spectrum E(k) is given by Eq. (1.3.22) of Lect. 4. The mass m* is
defined by the behavior of E(k) at k G/2:
h?q?
G
G
k «
2
E(k) = Em
2m**
2
Can m* be smaller or larger than the free electron mass?
Transcribed Image Text:Calculate the effective mass m* of electron with the momentum k G/2 in a weak periodic potential U(x) = 2Uo cos(27x/a) for which the energy spectrum E(k) is given by Eq. (1.3.22) of Lect. 4. The mass m* is defined by the behavior of E(k) at k G/2: h?q? G G k « 2 E(k) = Em 2m** 2 Can m* be smaller or larger than the free electron mass?
E2,1 (k) =
"
(Er + Ek-G) ± V(ER
(Ek- Ek-G)2 +U;
(1.3.22)
Transcribed Image Text:E2,1 (k) = " (Er + Ek-G) ± V(ER (Ek- Ek-G)2 +U; (1.3.22)
Expert Solution
Step 1

We have given that 

E(k)=Em-ħ2q22m*

Let us have an external force F is applied to electron in the band.

The work done in δE=Fvδt where, v is the velocity and δt in the time.

Now,

 δE=dEdkδk=ħvδk (from band theory)And Now combining the above two equation and dividing by δtwe get,F=ħdkdt  (Considering δt0)    .....(1)

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