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Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO,) solution? H,PO.(aq) + H,0(1) = H;O*(aq) + H2PO, (aq) K, = ¯ H&PO (aq) + H;O(1) = H,O*(aq) + HPO,*"(aq) K, 2 = 6.3×10¯º HPO (aq) + H,O(1) = H;O^(aq) + PO, (aq) Ka3 = 4.2×10¬" 7.1x10 %3D O a. pH = 0.948; [PO,"] = 2.38×10 1º M. %3D O b. pH = 0.875; [PO,"]= 1.99×10¬1º M Oc. pH = 0.986; [PO,"1 = 2.56×101º M O d. pH = 0.924; [PO,"1 = 2.22× 101º M O e. pH = 0.898; [PO, ] = 2.09×10*° M

Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO,) solution? H,PO.(aq) + H,0(1) = H;O*(aq) + H2PO, (aq) K, = ¯ H&PO (aq) + H;O(1) = H,O*(aq) + HPO,*"(aq) K, 2 = 6.3×10¯º HPO (aq) + H,O(1) = H;O^(aq) + PO, (aq) Ka3 = 4.2×10¬" 7.1x10 %3D O a. pH = 0.948; [PO,"] = 2.38×10 1º M. %3D O b. pH = 0.875; [PO,"]= 1.99×10¬1º M Oc. pH = 0.986; [PO,"1 = 2.56×101º M O d. pH = 0.924; [PO,"1 = 2.22× 101º M O e. pH = 0.898; [PO, ] = 2.09×10*° M

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 151QRT: A mountain lake that is 4.0 km × 6.0 km with an average depth of 75 m has an H+(aq) concentration of...
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Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO.) solution? H3PO,(aq) + H2O(1) = H;O^(aq) + H,PO, (aq) Ka1 = 7.1×10 H2PO, (aq) + H,O(1) = H,O*(aq) + HPO,² (aq) K, 2 = 6.3×10¯ HPO (aq) + H,O(1) = H;O*(aq) + PO," (aq) K,3 = 4.2×101³ O a. pH = 0.948; [PO,"] = 2.38×10 *° M. on O b. pH = 0.875; [PO,"] = 1.99×10¬1º M Oc pH = 0.986; [PO, 1 = 2.56×10¬1ª M O d. pH = 0.924; [PO,"] = 2.22×10¬1° M O e. pH = 0.898; [PO,1 = 2.09×10 1º M
Transcribed Image Text:Calculate the pH and PO, concentration in 2.25 M phosphoric acid (H;PO.) solution? H3PO,(aq) + H2O(1) = H;O^(aq) + H,PO, (aq) Ka1 = 7.1×10 H2PO, (aq) + H,O(1) = H,O*(aq) + HPO,² (aq) K, 2 = 6.3×10¯ HPO (aq) + H,O(1) = H;O*(aq) + PO," (aq) K,3 = 4.2×101³ O a. pH = 0.948; [PO,"] = 2.38×10 *° M. on O b. pH = 0.875; [PO,"] = 1.99×10¬1º M Oc pH = 0.986; [PO, 1 = 2.56×10¬1ª M O d. pH = 0.924; [PO,"] = 2.22×10¬1° M O e. pH = 0.898; [PO,1 = 2.09×10 1º M
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