Case Study #1 Setting: Small city in rural Missouri with an unchlorinated water supply. Subjects: Residents and visitors to this small town who developed bloody diarrhea and abdominal cramps between 15-December-1989 and 20-January-1990. During this time, 243 case patients were identified…..86 developed bloody stool, 32 were hospitalized, 4 died, and 2 developed hemolytic uremic syndrome. The CDC was called in to investigate the outbreak and took water samples for analysis. After isolating several microbes, the scientists at the CDC performed a number of biochemical tests to determine the nature of these organisms. The results will be

Case Study #1 Setting: Small city in rural Missouri with an unchlorinated water supply. Subjects: Residents and visitors to this small town who developed bloody diarrhea and abdominal cramps between 15-December-1989 and 20-January-1990. During this time, 243 case patients were identified…..86 developed bloody stool, 32 were hospitalized, 4 died, and 2 developed hemolytic uremic syndrome. The CDC was called in to investigate the outbreak and took water samples for analysis. After isolating several microbes, the scientists at the CDC performed a number of biochemical tests to determine the nature of these organisms. The results will be

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter18: Glycolysis

Section: Chapter Questions

Problem 14P: Energetic of Fructose-1 ,6-bis P Hydrolysis (Integrates with Chapter 3.) The standard free energy...

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Example of a Protein Purification Scheme: Purification of the Enzyme Xanthine Dehydrogenase from a Fungus Volume Total Total Specific Percent Fraction (mL) Protein (mg) Activity Activity Recovery 1. Crude extract 2. Salt precipitate 3. Ion-exchange chromatography |4. Molecular-sieve chromatography 5. Immunoaffinity chromatography 3,800 22,800 2,460 0.108 100 165 2,800 1,190 0.425 48 65 100 720 7.2 29 40 14.5 23 1.8 275 152.108 11 Calculate the specific activity of step#4. Note that percent recovery=% Yield.
nfile.php/7382360/mod_resource/content/0/Pyrimidine%20Practice%20Pat 1 / 1 67% + | 田 Pyrimidine Synthesis El * be surc to label reguletary Steps K carbamay1 phiuphate E2 orotate R-5P Eg UMP d TMP ATP ADPEE3 TET EedUDP O dumP E4 E5 CTP-> dCDP
B. COLOR REACTIONS. Give the ideal observation for the positive results of the following samples to complete the table below. Write NO RXN if the sample gives negative result for the given tests BIURET XANTHOPROTEIC NINHYDRIN SULFUR SAMPLES TEST TEST TEST TEST Formation of violet- Cysteine NO RXN colored product Formation of red- Tryptophan NO RXN colored solution Formation of Formation of violet- Keratin black colored product precipitate B - Alanine NO RXN NO RXN
Order the steps of the Edman degradation. Not all the steps are used. extract the derivatized amino acid First Last Answer Bank treat with trifluoroacetic acid identify the phenylthiohydantoin treat with 6 M HCI treat with dinitrofluorobenzene treat with phenyl isothiocyanate
Hydrolysis of polysaccharidesa. Add 20 drops of concentrated HCl to 30 mL of 3 % starch solution. Cover the beaker containing the mixture with a watch glass and boil gently. b. After one minute addition of acid solution, remove 2 drops of the solution and place on a spot plate. Test each spot with one drop of iodine solution. c. Perform the same test using Benedict’s solution instead of iodine solution. Hydrolysis of polysaccharides Results Starch Solution Iodine's Test Benedict's Test
Topic: Pharmaceutical chemistry. Biosynthesis of secondary metabolites. 1. Circle the biosynthetic units of crosanthin O and name them .COOH HO Figure. Structure of Crosanthin O (from Gardenia jasminoides fruits)
Why is the Mucic Acid test specific for the presence of galactose? Please explain do not copy from google, type the answer if u can
BIOMOLECULES Please answer the questions properly. - Multiple choice Qyestion 1: If a cell has an adequate supply of adenine nucleotides but requires more guanine nucleotides for protein synthesis: 1. Glutamine-PRPP amidotransferase will not be fully inhibited. 2. AMP will be a feedback inhibitor of the condensation of IMP with aspartate. 3. ATP will stimulate the production of GMP from IMP. 4. ATP will inhibit nucleoside diphosphate reductase. А. 1, 2, and 3 В. 2 and 4 С. 1, 2, 3, and 4 D. 1 and 3
These are option to choose and fill. 1.a.very acidicb.neutralc.very basic 2.a.asparagine and glutamineb.arginine and lysinec.phenylalanine and tyrosine 3.a.neutralb.negatively chargedc.aromaticd.positively charged 4.a.negatively charged phosphatesb.positively charged phosphatesc.aromatic nucleotidesd.neutral phosphoric acid groups 5.a.lose their aromatic side chainsb.lose their positive chargec.lose their negative charged.increase their positive chargee.increase their negative charge 6.a.more attraction to the phosphatesb.no attraction to the phosphatesc.no attraction to the aromatic groups 7.a.not as unfavorable becauseb.even less favorable becausec.comparatively favorable even though 8.a.carry negative chargesb.carry positive chargesc.are neutral
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5. Matching Type Match Column A with Column B. Write your answer on the space provided. CAPITAL letters only. Column A Column B 1.. Citrate → Isocitrate 2. Fumarate → Malate 3. Fructose-1,6-bisphosphate → G3P and DHAP 4. PEP → Pyruvate 5. a-Ketoglutarate → Succinyl-CoA 6. Substrate-level phosphorylation 7. Oxidative decarboxylation 8. Reduction 9. Isomerization 10. Condensation 11. Fumarate → Malate 12. Citrate → Isocitrate 13. Succinate → Fumarate 14. Succinyl-CoA → Succinate 15. Malate → Oxaloacetate 16. Pyruvate → Acetaldehyde 17. Pyruvate → Acetyl-CoA 18. PEP → Pyruvate 19. 2-Phospoglycerate → PEP 20. Glucose Glucose-6-phosphate A. Succinate dehydogenase B. Succinyl-CoA synthetase C. Malate dehydrogenase D. Fumarase E. Citrate synthase E. Isocitrate → a-Ketoglutarate F. 3-Phosphoglycerate → 2-Phosphoglycerate F. Aconitase G. Acetyl-CoA + Oxaloacetate → Citrate G. Glycolysis H. Pyruvate → Lactate I. Glucose-6-phosphate → Fructose-6-Phosphate K. Kreb's cycle U. Enolase V. Hexokinase…
I. True or False ____________9] Ribulose yields 5-hydroxymethylfurfural upon treatment with strong acid.___________10] Galactose gives a positive result with Benedict’s test faster than lactose due to the acidity of the reagent used.