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Enter your answer in the provided box. From the following heats of combustion, 3 CH₂OH() + O₂(g) → CO₂(g) + 2H₂O(1) 2 C(graphite) + O2(g) → CO₂(g) 1 H₂(g) + O₂(g) → H₂O(1) 2 1 C(graphite) + 2H₂(g) + O₂(g) → CH₂OH(1) ΔΗ kJ/mol rxn 0 ΔΗ =-393.5 kJ/mol rxn =-726.4 kJ/mol ΔΗ = -285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements:

Enter your answer in the provided box. From the following heats of combustion, 3 CH₂OH() + O₂(g) → CO₂(g) + 2H₂O(1) 2 C(graphite) + O2(g) → CO₂(g) 1 H₂(g) + O₂(g) → H₂O(1) 2 1 C(graphite) + 2H₂(g) + O₂(g) → CH₂OH(1) ΔΗ kJ/mol rxn 0 ΔΗ =-393.5 kJ/mol rxn =-726.4 kJ/mol ΔΗ = -285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements:

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 33PS: Nitrogen monoxide, a gas recently found to be involved in a wide range of biological processes,...
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Enter your answer in the provided box. From the following heats of combustion, 3 CH₂OH() + O₂(g) → CO₂(g) + 2H₂O(1) 2 C(graphite) + O2(g) → CO₂(g) 1 H₂(g) + O₂(g) → H₂O(1) 2 1 C(graphite) + 2H₂(g) + O₂(g) → CH₂OH(1) ΔΗ kJ/mol rxn 0 ΔΗ =-393.5 kJ/mol rxn =-726.4 kJ/mol ΔΗ = -285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements:
Transcribed Image Text:Enter your answer in the provided box. From the following heats of combustion, 3 CH₂OH() + O₂(g) → CO₂(g) + 2H₂O(1) 2 C(graphite) + O2(g) → CO₂(g) 1 H₂(g) + O₂(g) → H₂O(1) 2 1 C(graphite) + 2H₂(g) + O₂(g) → CH₂OH(1) ΔΗ kJ/mol rxn 0 ΔΗ =-393.5 kJ/mol rxn =-726.4 kJ/mol ΔΗ = -285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements:
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