Colorblindness is a sex-linked trait. If a heterozygous female crosses with a colorblind male, what are the possible genotypes of the offspring?
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Colorblindness is a sex-linked trait. If a heterozygous female crosses with a colorblind male, what are the possible genotypes of the offspring?
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- In currant moths, their Light color is sex-linked and recessive (d) to dark color (D). Question: What are the genotype and the phenotype of the parents if a certain cross yields ½ dark and ½ light colored females and all dark males? Take note that female moths are heterogametic.In cats, S = short hair; s = long hair; XC = black coat; Xc = yellow coat; XCXc = tortoiseshell (calico) coat. If a long-haired yellow male is crossed with a tortoiseshell female homozygous for short hair, what are the expected phenotypic results?If body-color B is dominant to green body color b what would the genotype be for a heterozygous individual be? Using the blue B and a green b body color from above create a Punit square that represents the offspring of two heterozygous parents? what is the probability that they will have a child with a green body-color If the child is green what is its genotype? Cross a green parent with a homozygous blue parent. What color will their kids be?
- In dogs, black coat color (B) is dominant to yellow coat color (b), and straight fur (C) is dominant to curly fur (c). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex-linked. In a cross between two BbCc parents, given that an offspring has black coat color and straight fur, what's the probability that it is heterozygous for both genes? Give 2 digits past the decimals.Gene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?In mice, short hair is dominant over long hair. If a heterozygous shorthaired male is crossed with a heterozygous female, what are the genotypes of the parents?
- Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%In fruit flies, Cinnabar eyes are encoded by a recessive allele located on the X chromosome. If a female having cinnabar eyes is crossed with a wild-type male, what is the phenotypic ratio among male offspring?In Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vg
- In cabbage butterflies, White wings are dominant to yellow wings. If a heterozygous white-winged butterfly is crossed with a yellow-winged butterfly, what are the possible genotypes and phenotypes of the offspring and the percent chance for each?You are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange-haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "O" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). orange-haired females : blue-haired females : orange-haired male : blue haired males What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2).…You are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange- haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use,2:1 rather than 4:2). 1:1 € 1:1 1:1 orange-haired females : 1:1 orange-haired male : What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). 1:1 blue-haired females :…