Compare the alternatives below using AW and i = 10% per year C D -350,000 -35,000 35,000 8 First Cost, $ Annual operating cost, $/year Salvage value, $ Life, years -150,000 -10,000 15,000 10
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- For the cash flows shown, determine the incremental cash flow between machines B and A for (a) year 0, (b) in year 3, and (c) in year 6. Machine First Cost, $ АОС, $/year Salvage value, $ 3,000 Life, years B -15,000 -25,000 -1,600 -400 6,000 3 4 O (a) = -10000 (b) = -1800 (c) = 1200 %3D !3! O (a) = -10000 (b) = 13200 (c) = 4200 !3! %3! O (a) = -10000 (b) = 13200 (c) =6000 %3! %3D O (a) = -10000 (b) = 13200 (c) = 13200 %3DA company can purchase a certain machine or rent one. IF purchased, the machine will cost $15,000 and will have a 5-years life with a 10% salvage value and operating cost will be $8000 per year. If the machine is rented, it will cost $400 per day. At interest rate is 10% per year, the minimum number of days the machine be justify its purchase is *YOLO Construction Co. is planning to purchase a new truck Company uses MARR as 10%% per year. Evaluate the following two altematives by Present Worth Analysis using Least Common Multiple (LCM) technique. Select the PW value of Alternative A First Cost, $ -170000 -130000 Annual Income, S/year 22000 and increasing starting from year 1 by $500 each year 29000 Annual Cost, S/year -7000 -11000 Major Maintenance Cost, every 3 years, S Salvage Value, S Life, years |-10000 17000 10000 4 Select one: O a. -195520.8 O b. -146445.8 O c. -116200 O d. -191185 O é. -142110
- Why is it -1000 at NVP (Beta), not -10000You received a memo that you are appointed as the team leader for a new commercial building project. Based on the estimation, if your team will be using a steel, it will cost 80,000 per month and 145000 cost if glass. For the plan A, it has an annual maintenance cost is 25000, 1000 repair cost every 2 years and a salvage value of 3000 after 15 years. For the plan B, the repair cost is 3500 every 3 years, annual maintenance cost of 30000 and a salvage value of 1000 after 20 years. Compute for the capitalized cost if the money is worth 8% compounded annually and choose the best material for the project. CC Plan A = (2 decimal places) %3D СC Plan B %3 (2 decimal places)A large textile company is trying to decide which sludge dewatering process it should use ahead of its sludge drying operation. The costs associated with centrifuge and belt press systems are shown. Compare them on the basis of their annual worths using an interest rate of 10% per year. System First cost, $ Centrifuge -250,000 -31,000 Belt Press -170,000 -35,000 -26,000 10,000 4 AOC, $/year Overhaul in year 2, $ Salvage value, $ Life, years The annual worth of the centrifuge system is $- The system selected on the basis of the annual worth analysis is the (Click to select) ✓ system. 40,000 6 and the annual worth of the belt press system is $-
- Required information The TT Racing and Performance Motor Corporation wish to evaluate two alternative machines for NASCAR motor tune- ups. Machine First cost, $ Annual operating cost, $ per year Life, years Salvage value, $ R -250,000 -40,000 3 20,000 Use the AW method at 9% per year to select the better alternative. The annual worth of machine R is $- The better alternative is (Click to select) S -370,500 -50,000 5 20,000 and the annual worth of machine S is $-BVM manufactured and sold 25,000 small statues this past year. At that volume, the firm was exactly in a breakeven situation in terms of profitability. BVM’s unit costs are expected to increase by 30% next year. What additional information is needed to determine how much the production volume/sales would have to increase next year to just break even in terms of profitability? (a) Costs per unit (b) Sales price per unit and costs per unit (c) Total fixed costs, sales price per unit, and costs per unit (d) No data is needed, the volume increase is 25, 000 + 25, 000(0.30) = 32, 500 units.You received a memo that you are appointed as the team leader for a new commercial building project. Based on the estimation, if your team will be using a steel, it will cost 80,000 per month and 145000 cost if glass For the plan A, it has an annualmaintenance cost is 25000, 1000 repair cost every 2 years and a salvage value of 3000 after 15 years For the plan B, the repair cost is 3500 every 3 years, annual maintenance cost of 30000 and a salvage value of 1000 after 20 years. Compute for the capitalized cost if the money is worth 8% compounded annually and choose the best material for the project.CC PlanA = (2 decimal placesCC Plan B = (2 decimal places)
- Buying Equipment 1 from XYZ company and company ABC will give the production similar productivity input of 400,000.00 per year. The equipment from company XYZ has a purchase price of 200,000.00, annual maintenance of 5,000.00, and production life of 10 years, while the equipment from company ABC has a purchase price of 100,000.00, annual maintenance of 2,000.00, and production life of 12. Using present worth method, what is the present values of their purchase profit? Use MARR of 20%Buying Equipment 1 from XYZ company and company ABC will give the production similar productivity input of 400,000.00 per year. The equipment from company XYZ has a purchase price of 200,000.00, annual maintenance of 5,000.00, and production life of 10 years, while the equipment from company ABC has a purchase price of 100,000.00, annual maintenance of 2,000.00, and production life of 12. Using present worth method, what is the total present worth of each alternatives? Use MARR of 20%Which alternative in the table below should be selected when the MRR = 6% per year? The life of each Kalternative is 10 years. Increment Considered A Investment cost A (Annual Revenues less. Costs) IRR on A Investment Cost A(A-DN) $800 $154 14.1% The IRR on A(C-B) is %. (Round to one decimal place.) A(B-A) $700 $114 10.0% A(C-B) $1,100 $170 ? A(D-C) $1,300 $130 2