Complete the code.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Complete the code.
![Write a function valid Solution/ValidateSolution/valid_solution ()
that accepts a 2D array representing a Sudoku board, and returns true
if it is a valid solution, or false otherwise. The cells of the sudoku
board may also contain 0's, which will represent empty cells.
Boards containing one or more zeroes are considered to be invalid solutions.
The board is always 9 cells by 9 cells, and every cell only contains integers
from 0 to 9.
(More info at: http://en.wikipedia.org/wiki/Sudoku)
#Using dict/hash-table
from collections import defaultdict
def valid_solution_hashtable(board):
for i in range(len (board)):
dict_row=defaultdict(int)
dict_col=defaultdict(int)
forj in range(len (board[0])):
value_row = board [i][j]
value_col=board [j][i]
if not value_row or value_col== 0:
return False
if value_row in dict_row:
return false
else:
dict_row[value_row] += 1
if value_col in dict_col:
return False
dict_col[value_col] += 1
else:
for i in range(3):
forj in range(3):
grid_add = 0
fork in range(3):
for l in range(3):
grid_add += board [i*3 + k][j* 3+1]
if grid_add != 45:
return False
return True
# Without hash-table/dict
def valid_solution (board):
correct = [1, 2, 3, 4, 5, 6, 7, 8, 9]
#check rows
for row in board:
if sorted (row) != correct:
return false
# check columns
for column in zip (*board):
if sorted (column) != correct:
return false
#check regions
for i in range(3):
for j in range(3):
region = []
for line in board [i*3:(i+1)*3]:
region += line[j*3:(j+1)*3]
if sorted (region) != correct:
return False
# if everything correct
return True
# Using set
def valid_solution_set(board):
valid = set(range(1,10))
for row in board:
if set(row)!= valid:
return false
for col in [[row[i] for row in board] for i in range(9)]:
if set(col) != valid:
return false
for x in range(3):
fory in range(3):](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c7426cd-cd02-4800-b0a3-4b0b7f7d4ffa%2F7d49a5d5-4739-4913-b267-5807a5724a78%2F56tqsfd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Write a function valid Solution/ValidateSolution/valid_solution ()
that accepts a 2D array representing a Sudoku board, and returns true
if it is a valid solution, or false otherwise. The cells of the sudoku
board may also contain 0's, which will represent empty cells.
Boards containing one or more zeroes are considered to be invalid solutions.
The board is always 9 cells by 9 cells, and every cell only contains integers
from 0 to 9.
(More info at: http://en.wikipedia.org/wiki/Sudoku)
#Using dict/hash-table
from collections import defaultdict
def valid_solution_hashtable(board):
for i in range(len (board)):
dict_row=defaultdict(int)
dict_col=defaultdict(int)
forj in range(len (board[0])):
value_row = board [i][j]
value_col=board [j][i]
if not value_row or value_col== 0:
return False
if value_row in dict_row:
return false
else:
dict_row[value_row] += 1
if value_col in dict_col:
return False
dict_col[value_col] += 1
else:
for i in range(3):
forj in range(3):
grid_add = 0
fork in range(3):
for l in range(3):
grid_add += board [i*3 + k][j* 3+1]
if grid_add != 45:
return False
return True
# Without hash-table/dict
def valid_solution (board):
correct = [1, 2, 3, 4, 5, 6, 7, 8, 9]
#check rows
for row in board:
if sorted (row) != correct:
return false
# check columns
for column in zip (*board):
if sorted (column) != correct:
return false
#check regions
for i in range(3):
for j in range(3):
region = []
for line in board [i*3:(i+1)*3]:
region += line[j*3:(j+1)*3]
if sorted (region) != correct:
return False
# if everything correct
return True
# Using set
def valid_solution_set(board):
valid = set(range(1,10))
for row in board:
if set(row)!= valid:
return false
for col in [[row[i] for row in board] for i in range(9)]:
if set(col) != valid:
return false
for x in range(3):
fory in range(3):
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