Consider a mixture of two proteins with molecular weights of 20,000 and 200,000. For simplicity of calculation, both may be approximated as unhydrated spheres with vg 0.740 mL g¬l. B a. Calculate the ratio of the sedimentation coefficients of the proteins in the same medium (density= 1.05 g mL-I) at the same temperature.
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- You want to prepare a 15 mL gel containing 0.8% (weight /volume) agarose. How much agarosedo you need to weigh to prepare the solution? Show all your calculations.Hint: Write down the units for 0.8% knowing that agarose is a powder that is mixed with aliquidcan you show how to calculate the amount of two components for the required volume of a buffer with the receipes? Prepare enough 10X stock solution § Prepare 1LProportions§ 0.25M tris§ 1.92M glycine§ pH 8.3§ 1% (w/v) SDSInstructions to prepare 100mL of 10X running buffer1. Weigh 3.02g of Tris base and 14.42g of glycine into ~90mL of ddH2O in a clean beaker and stir todissolve.2. Check the pH with a calibrated pH metre once dissolved.§ The pH of the buffer should be 8.3. pH adjustment is not required if between 8.1-8.5.3. Add 5mL 20% (w/v) SDS stock solution (a liquid) to make a 1% (w/v) solution.4. Top the volume to 100mL by adding 5mL ddH2O from a graduated cylinder.An aqueous antifreeze solution is 45.0% ethylene glycol () by mass. The density of the solution is 1.05. Calculate the molality, molarity, and mole fraction of the ethylene glycol
- Solution Absorbance mg/ml aspirin Standard solution - 1.6 mg/mL A 0.638 0.08 mg/mL B 0.504 0.064 mg/mL C 0.376 0.048 mg/mL D 0.259 0.032 mg/mL E 0.126 0.016 mg/mL A = -log T where T = %T ÷ 100 Construct a callibration curve using the above data. Absorbance should be on the vertical axis and "mg/mL of acetylsalicylic acid" on the horizontal axis. The line should go through the origin. Using the data provided, the graph you have generated, and the procedure that was used to generate the solutions which were examined by spectroscopy, calculate the amount of acetylsalicylic acid per tablet. Commercial tablet 1 labelled as 100 mg enteric coated Absorbance = 0.16 Commercial tablet 2 labelled as 300 mg Absorbance = 0.45 Student prepared tablet from practical 5 Absorbance = 0.19 Using the data provided, the graph you have generated, and the procedure that was used…You have just used up the last of a 1.2 % m/m solution of agarose in water. You require another 100mls. How many grams of Agarose do you require? Note 1ml of water=1g What is the % w/v of a 100ml solution containing 5g of NaCl?What mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4. Please indicate the full solutions.
- 9. 3 μL of a 45 mM stock solution of a substrate is added to 8 mL of water. Calculate the following values. The substrate molecular weight is 125 g/mol. Substrate volume in mL Dilution factor Substrate number of moles Substrate concentration for the diluted solution in mM Substrate concentration for the diluted solution in mole/L Substrate concentration for the diluted solution in mg/mL1) Calculate the required gram of Tris-Hcl to prepare 1M, 100 ml Tris-HCl (Tris Stock) with mol and Molarity formula. 2)Calculate the required gram of EDTA to prepare O.5M, 100 ml EDTA (EDTA stock) mol and Molarity formula. 3.) Calculate the required volume of Tris Stock to prepare buffer A which contains 25 mM Tris-Hcl with final volume is 100 ml by using M1V1 =M2V2 formula 4) Calculate the required volume of EDTA stock to prepare buffer A which contains 10 mM EDTA with final volume is 100 ml by using M1V1 =M2V2 formula 5)Do the same for Buffer B calculationsThimerosal Tincture USP contains 0.1% w/v thimerosal and 50% v/v ethyl alcohol. If the cap is left off of a 15-mL bottle of the tincture, and the ethyl alcohol evaporates leaving a final volume of 9.5 mL, what is the concentration of thimerosal in the evaporated solution expressed as a ratio strength?
- You just made a 1.5M permanganate solution. What concentration is your potassium permanganate solution in percent? "K: 39.10 g/mole" "Mn: 54.94 g/mole" "O: 16 g/mole" "MW of KMnO4 is 158.04 g/mole" O a. 0.24% Ob. 20.1% O c. 15.8% O d. 23.7% O e. 2%Quinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =You need a buff er at pH 7.5 for use in purifying a protein at 4°C. You have chosen Tris, pK 8.08, ΔH° = 50 kJ · mol−1. You carefully make up 0.01 M Tris buffer, pH 7.5 at 25°C, and store it in the cold to equilibrate it to the temperature of the purifi cation. When you measure the pH of the temperature-equilibrated buff er it has increased to 8.1. What is the explanation for this increase? How can you avoid this problem?