Consider the following variables: Y=daily productivity score (measured in points) X1=0 if undergraduate student,1 if graduate student X2=hours of sleep per night 1. The plot shown below could possibly be the graph of which model? 2. If you want to test whether type of student modifies the association between hours of sleep per night and daily productivity score, which model should you consider and what is the null hypothesis for this test?
Consider the following variables: Y=daily productivity score (measured in points) X1=0 if undergraduate student,1 if graduate student X2=hours of sleep per night 1. The plot shown below could possibly be the graph of which model? 2. If you want to test whether type of student modifies the association between hours of sleep per night and daily productivity score, which model should you consider and what is the null hypothesis for this test?
Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter4: Graphing And Inverse Functions
Section: Chapter Questions
Problem 6GP: If your graphing calculator is capable of computing a least-squares sinusoidal regression model, use...
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Consider the following variables:
Y=daily productivity score (measured in points)
X1=0 if undergraduate student,1 if graduate student
X2=hours of sleep per night
1. The plot shown below could possibly be the graph of which model?
2. If you want to test whether type of student modifies the association between hours of sleep per night and daily productivity score, which model should you consider and what is the null hypothesis for this test?
3. Suppose you use Model 5 to describe the relationship between type of student, hours of sleep per night, and daily productivity score. You use the method of least squares to obtain: Y = -0.5 + 3 (X1) + 1.5 (X2) + 2.5 (X1)(X2).
Transcribed Image Text:Mean Y
Model 1: Y =
X₁ = 1
X₁ = 0
(a)
Model 2: Y = Bo + B₁X₁ + ε
Model 3: Y = B₁
Bo
+ B₂X₂ + ε
Model 4: Y = Bo + B₁X₁ + B₂X₂ + ε
= Bo
Model 5: Y = Bo + B₁X₁ + B₂X₂ + ß3X₁X₂ + ε
X₂
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