Consider the reaction below: 2KC103(s)-2KCl(s) + 30₂(g) Given Molarmass: KClO3 (122.6 g/mol); KCl (74 g/mol); O₂ (32 g/mol) R = 0.082 L.atm/mol.K What will be the mass of KCl produced if we got 68 L of oxygen gas upon decomposition of KClO3 at STP conditions

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