Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> MW = 26 36.5 C₂H4Cl2 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?
Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> MW = 26 36.5 C₂H4Cl2 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?
Chapter5: Chemical Reactions
Section: Chapter Questions
Problem 5.88E
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