Considering the chemical equation below: 4 C3H5BR3 + 17 02 12 CO2 + 10 H20 + 6 Br2 What is the maximum amount of bromine (Br2) that can be obtained from mixing 38.2 g of C3H5Br3 with 24.6 g of O2 (Mw of CzH5Br3 = 280.78 amu, O2 = 32.00 amu and Br2 = 159.81 amu)? %3D O 32.6 g O 21.8 g 43.3 g O 7.65 g O 34.4 g

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Problem 4.21PAE: 4.21 Ammonium nitrate, NH4NO3, will decompose explosively to form N2, O2, and H2O, a fact that has...
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Considering the chemical equation below:
4 C3H5BR3 + 17 02 12 CO2 + 10 H20 + 6 Br,
What is the maximum amount of bromine (Br2) that can be obtained from mixing
38.2 g of C3H5BR3 with 24.6 g of O2 (Mw of C3H;Br3 = 280.78 amu, O2 = 32.00 amu
and Br, = 159.81 amu)?
O 32.6 g
O 21.8 g
43.3 g
7.65 g
34.4 g
Transcribed Image Text:Considering the chemical equation below: 4 C3H5BR3 + 17 02 12 CO2 + 10 H20 + 6 Br, What is the maximum amount of bromine (Br2) that can be obtained from mixing 38.2 g of C3H5BR3 with 24.6 g of O2 (Mw of C3H;Br3 = 280.78 amu, O2 = 32.00 amu and Br, = 159.81 amu)? O 32.6 g O 21.8 g 43.3 g 7.65 g 34.4 g
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