Convert unsigned decimal 60293 to a hexadecimal value. 1656 いr6u293
Chapter6: Looping
Section: Chapter Questions
Problem 8RQ
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Question
Assembly Programming question:
Convert unsigned decimal 60293 to a hexadecimal value
Transcribed Image Text:4. Convert unsigned decimal 60293 to a hexadecimal value.
3 -R
いrou293
example, let's add the hexadecimal values 6A2 and 49A. In the lowest digit position, 2 + A = decimal 12, so there is no carry and we use C to indicate the hexadecimal sum digit. In the next
16 6
ding Hexadecimal
tion. A + 9 = decimal 10
JOn 16-3 and carry a 1 into the third digit position. Finally, we add 1 +6+ 4 = decimal 11
Expert Solution
Step 1
Assembly code to convert decimal 60293 to hexadecimal:
.MODEL SMALL
.STACK 100H
.DATA
d1 dw 60293
.CODE
MAIN PROC FAR
MOV AX,
@DATA
MOV DS,
AX
in variable d1
mov ax,
d1
print the value
CALL PRINT
MOV AH,
4CH INT 21H
MAIN ENDP
PRINT PROC
mov cx,
0 mov dx, 0 label1:
ax is zero
cmp ax,
0 je print1
div bx
push dx
inc cx
xor dx,
dx
jmp label1
print1:
cmp cx,
0 je exit
pop dx
value is greater than 9
add dx,
7
continue:
add dx,
48
character
mov ah,
02h int 21h
dec cx
jmp print1
exit : ret
PRINT ENDP
END MAIN
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