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Create a pseudocode (if you not familiar with this, you can create a program) that check if "directed graph" is actually circle graph. The meaning of circle is that let's say there is 1~6 nodes. The graph start with 1 and only can move to 2, and 2 can only move to 3....etc and after you hit 6, you move back to 1. so 1=>2=>3=>4=>5=>6=>1 this is example of circle directd graph. Please create a pseudocode/program to check if graph is circle or not. Also, include the time complexity of your pseudocode by [Worst case time complexity / Best case time complexity]

Create a pseudocode (if you not familiar with this, you can create a program) that check if "directed graph" is actually circle graph. The meaning of circle is that let's say there is 1~6 nodes. The graph start with 1 and only can move to 2, and 2 can only move to 3....etc and after you hit 6, you move back to 1. so 1=>2=>3=>4=>5=>6=>1 this is example of circle directd graph. Please create a pseudocode/program to check if graph is circle or not. Also, include the time complexity of your pseudocode by [Worst case time complexity / Best case time complexity]

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Programming Language: C++

Create a pseudocode (if you not familiar with this, you can create a program) that check if "directed graph"

is actually circle graph. The meaning of circle is that let's say there is 1~6 nodes.

The graph start with 1 and only can move to 2, and 2 can only move to 3....etc and after you hit 6, you move back to 1.

so 1=>2=>3=>4=>5=>6=>1

this is example of circle directd graph. Please create a pseudocode/program to check if graph is circle or not.

Also, include the time complexity of your pseudocode by [Worst case time complexity / Best case time complexity]

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