create a python code that utilizes strain formula using python programming language
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create a python code that utilizes strain formula using python
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- plz need soultion asap and thanksMAX _ no.A valid postal code have to fullfil both below requirements: must be a number in the range from to inclusive. must not contain more than one alternating repetitive digit pair. Alternating repetitive digits are digits which repeat immediately after the next digit. In other words, an alternating repetitive digit pair is formed by two equal digits that have just a single digit between them. For example: 121426#Here,1isanalternatingrepetitivedigit.523563#Here,NOdigitisanalternatingrepetitivedigit.552523#Here,both2and5arealternatingrepetitivedigits. Your task is to provide two regular expressions regex_integer_in_range and regex_alternating_repetitive_digit_pair. Where: regex_integer_in_range should match only integers range from to inclusive regex_alternating_repetitive_digit_pair should find alternating repetitive digits pairs in a given string. Both these regular expressions will be used by the provided code template to check if the input string is a valid postal code using the…
- го, r10 Øx51dd4 ldrex ro, [r6] го, г5 Оx51а14 strex r1, r4, (r6] г1, #0 Øx51a04 Оx519fe: mov bl Оx51а00: Øx51a04: Оx51а08: cmp bne 0x51а0а: flag.compare_exchange_strong (...) Оx51а0с: Øx51a10: cmp bne Øx51a12: ro, #0 Øx519fe го, [r11] г8, г8, #1 ro, #1 го, [r11] г5, [r6] ro, #38527 ro, #152 г8, го Øx519fe Оx51а14: cmp bne ldr.w add.w Øx51a16: Øx51a18: Оx51а1с: sharedValue++ Øx51a20: adds Оx51а22: str.w flag.store (...) Øx51a26: str Оx51а28: movw Оx51а2с: movt Оx51а30: cmp ble Оx51а32:• L₂ = {w = {a,b,c}* | w = b(a\b \cb)*a}PLS HELP HURRY
- The highlighted option is incorrect fyi.Saldizzoq eis zarieinit WOH230 W ynem word so Evaluate: C(7,6), then list the combinations. Use Set A = {a,b,c,d,e,f,g}Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. Suppose the initial value of the sequence number is 111 and every segment sent to the receiver each contains 194 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. And every segment needs to be acknowledged. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but one of the ACKS is lost. Assume there are no timeouts and any out of order segments received are thrown out. TCP sender TCP receiver t= 1 1= 2 data segment t= 3 data segment > t= 4 data segment> t= 5 data segment > data segment P t = 8 -t%= 9 t= 10 = 11 * ACK segment ACK segment ACK segment t= 12 ACK segment t = 15- t= 16 t= 17 t = 18