Create using C-Language Create a Program that asks for 10 integers (Use Arrays). Afterward, display a navigation menu and perform the following: Display the numbers Display it in reverse order Display the values of even indices (0th, 2nd, 4th, 6th, 8th, …, 2n) Display the values of odd indices (1st, 3rd, 5th, 7th, 9th,.., 2n+1) Ask for an index k, then rotate array to the right. Ask for an index k, then rotate the array to the left.
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Create using C-Language
Create a Program that asks for 10 integers (Use Arrays). Afterward, display a navigation menu and perform the following:
- Display the numbers
- Display it in reverse order
- Display the values of even indices (0th, 2nd, 4th, 6th, 8th, …, 2n)
- Display the values of odd indices (1st, 3rd, 5th, 7th, 9th,.., 2n+1)
- Ask for an index k, then rotate array to the right.
- Ask for an index k, then rotate the array to the left.
Step by step
Solved in 4 steps with 9 images
- Output differs. See highlights below. Input 17 5 Your output 17 12 7 2 0 2 7 12 17 Expected output 17 12 7 2 -3 2 7 12 17• The game begins by welcoming the user and asking their name. • Then it displays the rules of the game and a menu to the user. The menu must display the options to select the doors, the value of the treasures behind each door, and the minimum token required to open those doors (see the sample outputs below to get an idea). • Now the user can select a door of their choice or decide to quit the game. Note that the user is allowed to type incorrect inputs. If they do not type a valid option, your program should print an error message and show the menu again. (Hint: you can use a while loop to help with this.) • The user has a chance to change their mind at this stage and choose another door if they wish but they cannot quit now. Again, the user input must be validated. Note that user inputs that are of type strings are not case-sensitive. • Next, the magic wheel randomly generates a token. • Your program must display the token’s type to the user and decide if that is sufficient to open…Please describe what this testbench code is doing. You can use comments for each line if that is easier for you. This code is using Verilog. `timescale 1ns / 1ps module display_tb02(); reg [4:0] P; reg [1:0] X; wire [3:0] an; wire [0:7] led; Disp_tester uut( .P(P), .X(X), .an(an), .led(led) ); initial begin $display("\nTestbench start"); {P,X}=0; //quantity formed by concatenating....initialized to 0 #100; end always begin #10; //wait for 10 * 1ns = 10ns if ({P,X} === 'b1111111) begin #10; $display("Testbench end"); $finish; end else begin {P,X} = {P,X} + 1; $display("P,X=%0d,%0d",P,X); $display("an,led=,%b,%b",an,led); end end endmodule
- Java Script There is a single operator in JavaScript, capable of providing the remainder of a division operation. Two numbers are passed as parameters. The first parameter divided by the second parameter will have a remainder, possibly zero. Return that value. Examples remainder(1, 3) → 1 remainder(3, 4) → 3 remainder(-9, 45) → -9 remainder(5, 5) → 0 Notes The tests only use positive and negative integers. Don't forget to return the result.Please solve this using java Write an application that allows a user to enter the names and birth dates of up to 10 friends. Continue to prompt the user for names and birth-dates until the user enters the sentinel value “ZZZ” for a name or has entered 10 names, whichever comes first. When the user is finished entering names, produce a count of how many names were entered, and then display the names. In a loop, continuously ask the user to type one of the names and display the corresponding birth-date or an error message if the name has not been previously entered. The loop continues until the user enters “ZZZ” for a name.create a counter, which takes 2 numbers as parameter and show total number of counts to reach towards the number Hint: counter(Start,Stop, Count) where, Start is starting number and Start should be greater than 2. Stop is the ending number where your counter should stop. Count is total number of counts
- In this task, you are required to write a code which takes as an input an angle [0°, 90°] in radians and returns the approximate value of the cosine of this angle. The code will also take as an input the number of terms to be used to approximate the result. We will use the Maclaurin series of cos(x) to approximate the result. The series is given by: cos(x) = Σn=0 -1"x2n (2n!) but for practical reasons, we will not use infinite terms but k terms where k is input by the user: cos(x) = Σ -1x2n 2n=0 (2n!) So, for example, to calculate the cosine for 60° (1.04667 radians) using five terms, the approximation will be: 1.04667² 1 1.04667¹ 4! 1.046676 1.046678 + 0.50046 2! 6! 8! • The program should at most handle 15 terms (to avoid overflows due to factorial), otherwise the program outputs Invalid • There should be at least three terms used in the approximation, otherwise the program outputs Invalid • If the number of terms is negative, the programs corrects it automatically to positive. • If…ShowCurrentTime.java, gives a program that displaysthe current time in GMT. Revise the program so it prompts the user to enter thetime zone offset to GMT and displays the time in the specified time zone. Here isa sample run: Enter the time zone offset to GMT: -5The current time is 4:50:34Assignment: Check the Sample run first, then carefully read the instructions and write aprogram that prompts the user for first name, last name, then secret number. The output willgenerate a default email address and a default password. 1. The main method will do the following:• Asks the user for first name, last name, and secret number using Scanner. (first lettercan be in upper case)• Call defaultInfo(String, String) method to PRINT default Kean email address.• Call defaultInfo(String, int) method to PRINT default Kean password.• Note: You are using overloaded methods (i.e., same method name with differentparameter lists) 2. Write an overloaded method, defaultInfo, which does the following:• public static void defaultInfo(String firstName, String lastName) [Note:you can use your own variable name]‒ print default email address all in low caps: concatenate first letter offirstName, full lastName, and @gmail.com. [Hint: string.charAt(index),string.toLowerCase()]• public static void…
- USE JAVA Write an application that allows a user to enter the names and birthdates of up to 10 friends. Continue to prompt the user for names and birthdates until the user enters the sentinel value ZZZ for a name or has entered 10 names, whichever comes first. When the user is finished entering names, produce a count of how many names were entered, and then display the names. In a loop, continuously ask the user to type one of the names and display the corresponding birthdate or "Sorry, no entry for name" if the name has not been previously entered. The loop continues until the user enters ZZZ for a name. An example of the program is shown below: Enter a name Lan Enter birthdate with slashes between the month, day, and year 12/25/1983 Enter a name or ZZZ to quit Marylouise Enter birthdate with slashes between the month, day, and year 2/20/1992 Enter a name or ZZZ to quit Arminda Enter birthdate with slashes between the month, day, and year 8/30/1992 Enter a name or ZZZ to quit Gudrun…Modify the below code according to what is asking you to do. Show your modified code in a picture, please.A Jupyter Notebook contains two code cells. The first one reads 1 import numpy as np 2 import matplotlib.pyplot as plt and produces no output. The second code cell produces the following output: y position 3 2 1 7 -2 -3 X = -3 -2 -1 In-term 1 1 X 2 T 3 5 Select all of the following lines of code that can be found in the second code cell. (Note that they may not appear in the order in which they were executed.) [-1.5, 1.0, -0.5, 0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0, 4.5] plt.plot(x, [1/_x if _x != 0 else np. nan for _x in x], color='blue', linestyle='solid', marker='0') Oplt.xlabel('x') Oplt.ylabel('y position') O plt.plot(x, [_x**2 for _x in x], color='blue', marker='x') plt. ylim(-4, 3) O plt.title('In-term 1') O plt.xlim (-3, 5) plt.show() X = np. linspace(-1, 5, 150)