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+ C↔XT H* Electrophilic aromatic substitution is a two-step process. In the first step an electrophile, here generically shown as Y+, reacts with the aromatic ring to form a resonance-stabilized carbocation intermediate. In the second step, loss of a proton from the site of attack restores aromaticity to the ring and completes the reaction. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions

+ C↔XT H* Electrophilic aromatic substitution is a two-step process. In the first step an electrophile, here generically shown as Y+, reacts with the aromatic ring to form a resonance-stabilized carbocation intermediate. In the second step, loss of a proton from the site of attack restores aromaticity to the ring and completes the reaction. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6=6 NaOH Halobenzenes that do not have electron-withdrawing groups can still undergo substitution under conditions of high temperature and pressure. The reaction proceeds via a triple-bond intermediate called benzyne. Normal triple bonds arise from the overlap of orthogonal p orbitals to form two pi bonds. In benzyne, the first pi bond is formed normally, but the second is formed via weak overlap of two sp² orbitals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 20 ↔XT OH H-OH H :OH
Transcribed Image Text:6=6 NaOH Halobenzenes that do not have electron-withdrawing groups can still undergo substitution under conditions of high temperature and pressure. The reaction proceeds via a triple-bond intermediate called benzyne. Normal triple bonds arise from the overlap of orthogonal p orbitals to form two pi bonds. In benzyne, the first pi bond is formed normally, but the second is formed via weak overlap of two sp² orbitals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 20 ↔XT OH H-OH H :OH
Arrow-pushing Instructions Electrophilic aromatic substitution a two-step process. In the first step an electrophile, here generically shown as Y+, reacts with the aromatic ring to form a resonance-stabilized carbocation intermediate. In the second step, loss of a proton from the site of attack restores aromaticity to the ring and completes the reaction. Draw curved arrows to show the movement of electrons in this step of the mechanism. NOC XT + y+ H* H
Transcribed Image Text:Arrow-pushing Instructions Electrophilic aromatic substitution a two-step process. In the first step an electrophile, here generically shown as Y+, reacts with the aromatic ring to form a resonance-stabilized carbocation intermediate. In the second step, loss of a proton from the site of attack restores aromaticity to the ring and completes the reaction. Draw curved arrows to show the movement of electrons in this step of the mechanism. NOC XT + y+ H* H
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