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d According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892

d According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Questions 6-8 are related 6 According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892 7 8 a b 9 с d a b с d a b с d a b с с d 10 Questions 9-11 are related to the following To build an interval estimate with a 95% level of confidence for the average weekly wage in Indiana a random sample of working adults provided the accompanying data (in dollars): a b с d 11 a b с d 12 a b Given = 40.5% and n = 610 above, the fraction of sample proportions that fall within ±0.03 (3 percentage points) from it is, с d 0.7841 0.8254 0.8688 0.9145 Given = 40.5% and n = 610 above, the lower and upper ends of the interval which captures 95 percent of all sample proportions is, 0.389 0.383 0.376 0.366 1150 1006 1089 1163 936 835 1125 1002 929 1122 892 962 924 736 967 1003 The point estimate of population mean weekly wage is, 929.74 978.67 0.421 0.427 0.434 0.444 1030.18 1084.40 995.99 987.44 960 1045 1163 1052.06 1057.53 1064.37 1072.92 868 1261 1070 1147 1135 851 1368 1175 730 1240 1319 1193 1193 1101 1164 817 1247 810 1187 941 818 878 967 738 844 1218 978 963 957 The interval estimate for the population mean weekly wage with a 95% confidence level is, 1008.30 1002.83 1245 1146 965 1350 1073 1116 1519 733 1170 1042 974 748 766 923 830 873 1204 1117 1149 1490 879 982 865 827 You want to achieve a margin of error of $20 for the 95% confidence interval for the population weekly wage rate. What is the minimum sample size to obtain this MOE? For planning value use the standard deviation from original sample. 318 306 294 283 Suppose 280 students are taking E270. Each student is assigned to take a random sample of 100 workers in Indiana and each build a 95% confidence interval for the average weekly wage. How many of these 280 intervals should we expect to capture the actual population mean weekly wage. 95 275 270 266
Transcribed Image Text:Questions 6-8 are related 6 According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892 7 8 a b 9 с d a b с d a b с d a b с с d 10 Questions 9-11 are related to the following To build an interval estimate with a 95% level of confidence for the average weekly wage in Indiana a random sample of working adults provided the accompanying data (in dollars): a b с d 11 a b с d 12 a b Given = 40.5% and n = 610 above, the fraction of sample proportions that fall within ±0.03 (3 percentage points) from it is, с d 0.7841 0.8254 0.8688 0.9145 Given = 40.5% and n = 610 above, the lower and upper ends of the interval which captures 95 percent of all sample proportions is, 0.389 0.383 0.376 0.366 1150 1006 1089 1163 936 835 1125 1002 929 1122 892 962 924 736 967 1003 The point estimate of population mean weekly wage is, 929.74 978.67 0.421 0.427 0.434 0.444 1030.18 1084.40 995.99 987.44 960 1045 1163 1052.06 1057.53 1064.37 1072.92 868 1261 1070 1147 1135 851 1368 1175 730 1240 1319 1193 1193 1101 1164 817 1247 810 1187 941 818 878 967 738 844 1218 978 963 957 The interval estimate for the population mean weekly wage with a 95% confidence level is, 1008.30 1002.83 1245 1146 965 1350 1073 1116 1519 733 1170 1042 974 748 766 923 830 873 1204 1117 1149 1490 879 982 865 827 You want to achieve a margin of error of $20 for the 95% confidence interval for the population weekly wage rate. What is the minimum sample size to obtain this MOE? For planning value use the standard deviation from original sample. 318 306 294 283 Suppose 280 students are taking E270. Each student is assigned to take a random sample of 100 workers in Indiana and each build a 95% confidence interval for the average weekly wage. How many of these 280 intervals should we expect to capture the actual population mean weekly wage. 95 275 270 266
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