Define/code two non-composite processes in FSP, named EVEN and TRIPLE. EVEN process will take a non-negative integer and output the input number if it is even (e.g., 0, 2, and 4). TRIPLE process will take a non-negative integer and output the input number if it is triple (e.g., 0, 3 and 6). Define/code a FSP composite process, named TEST6, which includes both EVEN and TRIPLE processes. TEST6 process will take a non-negative integer and output the input number if it is a sextuple (e.g., 0, 6 and 12); otherwise, NO output. ( I REQUIRE ONLY THE TEST6 part "COMPOSITE PROCESS

Define/code two non-composite processes in FSP, named EVEN and TRIPLE. EVEN process will take a non-negative integer and output the input number if it is even (e.g., 0, 2, and 4). TRIPLE process will take a non-negative integer and output the input number if it is triple (e.g., 0, 3 and 6). Define/code a FSP composite process, named TEST6, which includes both EVEN and TRIPLE processes. TEST6 process will take a non-negative integer and output the input number if it is a sextuple (e.g., 0, 6 and 12); otherwise, NO output. ( I REQUIRE ONLY THE TEST6 part "COMPOSITE PROCESS

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter10: Application Development

Section: Chapter Questions

Problem 8VE

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Define/code two non-composite processes in FSP, named EVEN and TRIPLE. EVEN process will take a non-negative integer and output the input number if it is even (e.g., 0, 2, and 4). TRIPLE process will take a non-negative integer and output the input number if it is triple (e.g., 0, 3 and 6). Define/code a FSP composite process, named TEST6, which includes both EVEN and TRIPLE processes. TEST6 process will take a non-negative integer and output the input number if it is a sextuple (e.g., 0, 6 and 12); otherwise, NO output. Use LTSA to compile your code of EVEN, TRIPLE, and TEST6 processes and to show the corresponding LTS diagram for TEST6 process. Assuming all possible input integers to TEST6 process are from 0 to 12. Only show the input and output in the LTS diagram of TEST6 process.
Define/code two non-composite processes in FSP, named EVEN and TRIPLE. EVEN process will take a non-negative integer and output the input number if it is even (e.g., 0, 2, and 4). TRIPLE process will take a non-negative integer and output the input number if it is triple (e.g., 0, 3 and 6). Define/code a FSP composite process, named TEST6, which includes both EVEN and TRIPLE processes. TEST6 process will take a non-negative integer and output the input number if it is a sextuple (e.g., 0, 6 and 12); otherwise, NO output. PLEASE SEND THE EVEN AND TRIPLE AND SEXTUPLE "WORKING" COMPOSITE
Implementation of the solution in the C++ or Java language • Implementation of the solution in ARMv8 assembly, with comments explaining the purpose of each line Task 1 An automorphic number is a number n whose square ends in n. For instance, 5 is automorphic, because 52 = 25, which ends in 5. Design and implement an ARMv8 program that reads a positive integer from the user and then calculates and prints all the automorphic numbers (decimal base) that are less than or equal to the entered integer. If the entered integer is not positive, an error message is displayed. As an example, if 100 is entered, the program will print all the automorphic numbers up to 100: 1, 5, 6, 25, 76.
In Matlab, On a single page, type out an algorithm/pseudo-code that takes three 2D points as user input and outputs the geometric form that they make i.e. a point, a line or a triangle. The algorithm/pseudo-code should have 15-20 lines of text and no more than half of the lines should have code in them. The user should be asked for points consisting of integer x,y values and the algorithm should reject bad inputs.
Assignment for Computer Architecture The assignment is to create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The program’s output should look something like the following where the xxx’s are the numbers you chose. The resulting numbers may be different than mine depending on your choice of a, b, and c. Using a = xxx, b = xxx, and c = xxx a + (b + c) = 0 (a + b) + c = 1 The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. As a side note, the associative law will also fail for multiplication for floating point numbers, but you do not need to demonstrate that. Please don't forget to include comments in this code
Two processes are concurrently evaluating the expression (a + b) (c + d) - (e/f). Insert wait(S) and signal(S) operations into the code to enforce correct execution. The semaphore S, must guarantee that the additions must be completed before being used in the multiplication. Initialize the semaphore with the initial value. Process 1: tl = a + b; Process 2: t2 =c + d; t4 = t1*t2; t5 = t4 - t3; t3 = e/f; The positions of instructions are given as line numbers. Copy and paste wait(S) in the position where you would insert the wait operation. Copy and paste signal(S) in the position number where you would insert the signal operation. (Note: exact matching needed, hence type correctly or copy and paste). Enter NA if nothing to insert (Do not leave it blank). Process 1: 1. P1- 2. t1 - a + b: 3. P3- 4. t4 - t1*t2: 5. P5- 6. t5 - t4 - t3; 7. P7= Process 2: 1. P21- 2. 12 -c+ d; 3. P23- 4. t3 - e/f; 5. P25-
Abstract: the main purpose of this experiment is build real time system using PPI 8255 to control devices connected to. Problem description: assume that there are two devices are connected to port A and two sensors are connected to port B of PPI 8255. They work according to the following table Sensors (S1S2) Devices (DID2) 00 01 01 10 10 11 11 00 Write a program to control these two devices according to the values of sensors.
C has many statements for decisions and loops, while MIPS has few. Which of the following do or do not explain this imbalance? Why? 1. More decision statements make code easier to read and understand. 2. Fewer decision statements simplify the task of the underlying layer that is responsible for execution. 3. More decision statements mean fewer lines of code, which generally reduces coding time. 4. More decision statements mean fewer lines of code, which generally results in the execution of fewer operations.
Explain why we use semaphore, discuss semaphore types and write code for wait and signal functions?
Draw a complete block diagram.
Consider the statements below and choose the corect option T: Mathematical functions are used to draw an image in random scan system. Il: Screen points/pixels are used to draw an image in raster scan system. Both are false I is false and II is true I is true and Il is false Both are true
One way to electrically or optically represent a binary 1 or 0 is to use the transition between a voltage level (for example, going from a state of no voltage to a state of voltage, or vice versa, on a copper cable) or the transition of having light or no light on a fiber-optic cable to represent a binary 1. Similarly, a binary 0 is represented by having no transition in a voltage level or light level from one time period to the next. This approach of representing binary digits is called state transition modulation.