Derive the truth table, simplified Boolean function (equation), and draw the logical diagram: Implement using NAND-NAND, F= B'+CD'(A+B)+A'BC
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- parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.Construct a circuit diagram that checks whether the two numbers A and B are in the ratio of 2:3. Also, derive the final Boolean equation for the function. F = 1 if A: B = 2: 3,0 otherwise Here, A and B both are 3 bit binary numbers. NB: You cannot use the IC of comparator, meaning for the comparison part, you need to draw the gate level diagram. You can use block level diagrams for the rest of the parts.3. Discussion: 1. Compare between BCD code & Excess-3 code? 2. What is the reason of inventing Excess-3 Codes? 3. Find the Excess-3 code of (83.67)10 and show your work? 4. Find the decimal number of (11110001101010)Excess-3 and show your work? 5. What is the Excess-3 code of (100100001111001)BCD ? Show and verify yourwork.
- T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of thesea) Create a 4 Variable Karnaugh Map in paper by mapping 1’s for given standard SOP Boolean expression. After mapping , make relevant groups within Karnaugh Map by considering rules for making groups for 4 variable Karnaugh Map. After making relevant grouping , extract the minimum SOP expression by considering rules for extracting minimum SOP using Karnaugh Map. * Standard SOP: *Create Circuit Diagram using logic gates and logic converter in Multisim for given standard SOP and minimum SOP which you have solved. Do make sure that truth table for both expressions should evaluate same result.Please design a 6:1 multiplexer following the below procedures with data inputs of D5, D4, D3,D2, D1, D0 and output of Y.1 How many select signals are needed for this Mux.2) List a truth table for this Mux. Note: for all the unused combinations of select signals, Y=D53) Develop an optimized function for this Mux.4) Sketch the logic diagram of implementing this 6:1 Mux.5) Write a complete VHDL structural model to implement the above 6:1 multiplexer. Assume allthe required sub-component (standard gates) VHDL models are given/known that you can use
- Kindly construct the circuit given below in logic.ly/demo/ and post screenshot of the circuit: SW1 SWo A (SW1) 0 0 1 1 LD Please complete the Truth Table for Circuit as below: Inputs B (SWO) 0 1 3 HALF ADDER CIRCUIT SCREENSHOT 0 1 Sum (LO) SUM In Table, what is the relation between inputs and carry outputs? Ans: In Table, what is the relation between inputs and sum outputs? Ans: Lo Cout Li Outputs Cout (L1)How to build this circuit? (on Digital or Logisim) Binary-coded decimal is an alternative method of representing integers using binary. In it, each base-10 digit is represented by four bits, thus each nibble takes one of 10 values (0000 through 1001). Therefore, using BCD, 42 (decimal) is represented as 0100 0010 (binary) and 196 (decimal) is represented as 0001 1001 0110 (binary). Create a circuit in Logisim that accepts as input a pair of two-digit integers represented as BCD and outputs their sum in BCD. Any and all Digital components are fair game. You can assume that all inputs will be valid BCD-encoded numbers.Convert the following pairs of decimal numbers to 6-bit, signed 1's-complement binary numbers and add them. State whether or not overflow occurs in each case. (Please show the steps as we did in Lecture 2. You may not get points by just simply stating overflow or not) a) 8 and 23 b) -8 and 23 c) 18 and -23 d) -18 and -23 Repeat Problem #1 for 7-bit, signed 2's-complement binary numbers.
- 1. Gray code to Binary converter: Gray code is one of the codes used in digital systems. It has the advantage over binary numbers that only one bit in the code word changes when going from one number to the next. (See Table 1). Design a combinational circuit with 4 inputs and 4 outputs that converts a four- bit gray code number into an equivalent four-bit Binary number. Use Karnaugh map technique for simplification. Use LogicWorks for pre-lab demonstrations. Select the library "7400dev.clf* in the Parts Palette and then select the XOR chip 74-86. This would give you a set of 4 XOR's as shown in Fig. 1, just like the hardware chip 74-86. You could use as many as needed from these XOR gates in your design. Get back to ALL LIBRARIES and select switches for the inputs and Binary Probes as indicators of the outputs. Verify your design in the pre-Lab. During the Lab construct the circuit and verify its operations.Create a truth table with four inputs A, B, C and D and one output, Y. The output is FALSE only when A B and C=D. Otherwise the output is TRUE. Draw the Kamaugh map. write the simplified SOP expression and sketch the gate-level schematic.Design counter that counts from 00 to 59, using the IC 74LS90 ripple counter and use two 7 segment display to display the result count. You can also use 7447 binary to 7-segment Display Decoder in logicworks.