des a 16-bit field, which is used to encode an imm During the "Instruction Decode" phase this 16-bit value is transformed into a walue. For each of the following values, provide 16-bit value that is stored instruction and the 32-bit value that is passed to the ALU. * Av7FE7
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- LIST P = 16F877AUsing INCLUDE "P16F877A.INC" and PWM (Pulse Width Modulation), write the microprocessor code that enables the fan to operate at 80% if the button on the 5th bit is pressed, and 30% if the button on the third bit is pressed.Q1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H ) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When sending the required byte, you must adhere to the following: The two high bits of the start bits(1 1) must be sent, after that the data bits are sent, after that the low bit of the stop bit (0) is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay timeQ1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)
- Q1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending the required byte, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baud rate delay time Transmit Set up Character Bit Counter • Send Start Bit No Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes • Add Parity if Necessary Send Two Stop Bits Return (a)25: . Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore the time delay due to the first and last instruction. DELAY: LDI R16, 30 AGAIN: LDI R17, 35 HERE: NOP NOP DEC R17 BRNE HERE DEC R16 BRNE AGAIN RET 26: Write a program to display 2 on 7 segment. A 7 segment is connected to PortD.Translate the following LEGv8 code to C. Assume that the variables f, g, h, i, and j are assigned to registers X0, X1, X2, X3, and X4, respectively. Assume that the base address of the arrays A and B are in registers X6 and X7, respectively. ADDI X9, X6, #8 ADD X10, X6, XZR STUR X10, [X9, #0] LDUR X9, [X9, #0] ADD X0, X9, X10
- * Direction flag can reset to be zero by CLC True O False O ADD is a data transfer instruction which is used to add byte to byte/word to .word true O False O instruction is used to loon a set of instructions till zero flag becomesWrite the C55x assembly code for each of the following C snippet code shown below. Assume the 8-bit values a, b, c, and d are stored in locations 0x300, 0x301, 0x302, and 0x303 respectively in the memory. Store the result x in location 0x304 and y in location 0x30C. Do not use software to generate the assembly code and comment your code. a. x = (a + b)2 - (c*d); b. for (j=256;j>128;j--) y = y + (c * d);Q2. Interface 4 digit displays (each digit is a 7-segment display) to the 80386DX microprocessor (32 bit data bus and 32 bit address bus) using 8255 PPI. The 8255 should function at I/O addresses that start at 200H. Then write a program to initialize the 8255 and multiplex the 4 digit display where the data, in 7-segment code, that is to be displayed is stored at memory location 2000H: 0100H.
- Q1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Of+CD!HID+[00 Yes SIDATA Read SID Start Bit? Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter All Bits Received? Add Bit to Previous Bits Go Back to Get Next Bit Return IMUNIUse the following data declarations: .data byte Val word Val sbyte 1, 2, 3, FCh word 1000h, 2000h, 3000h, 4000h dwordVal dword 34567890h, 90785634h, 0Ah, 33445566h Show the value of the final destination operand after each of the following code fragments has executed: (If any instruction/s is invalid, indicate "INV" as the answer and briefly explain why) a. mov bh,byteVal+2 b. mov edx,1 C. add dx,[wordVal+4] mov ecx,5 xchg ecx,[dwordVal+12] d. mov ah, byte Val+3 sub ah,[ byte Val+0] sub ah,[ byte Val +2] e. mov eax, dword ptr dwordVal+7 f. movsx cx,byteVal+3 answer bh= answer edx= answer ecx= answer ah= answer eax= answer (show your answer in binary) CX=Assignment for Computer Architecture! this is about hamming codes write the code IN MIPS ASSEMBLY LANGUAGE calculating hamming codes; The key to the Hamming Code is the use of extra parity bits to allow the identification of a single error. Create the code word as follows: Mark all bit positions that are powers of two as parity bits. (positions 1, 2, 4, 8, 16, 32, 64, etc.) All other bit positions are for the data to be encoded. (positions 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, etc.) Each parity bit calculates the parity for some of the bits in the code word. The position of the parity bit determines the sequence of bits that it alternately checks and skips.Position 1: check 1 bit, skip 1 bit, check 1 bit, skip 1 bit, etc. (1,3,5,7,9,11,13,15,...)Position 2: check 2 bits, skip 2 bits, check 2 bits, skip 2 bits, etc. (2,3,6,7,10,11,14,15,...)Position 4: check 4 bits, skip 4 bits, check 4 bits, skip 4 bits, etc. (4,5,6,7,12,13,14,15,20,21,22,23,...)Position 8: check 8 bits,…