Design a 3-bit counter which counts in the sequence: 001,100,101,111,110,010,011,001,... (a) Use S-R flip-flops
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Design a 3-bit counter which counts in the sequence:
001,100,101,111,110,010,011,001,...
(a) Use S-R flip-flops
(b)What will happen if the counter of a D flip-flop is started in state 000?
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- 5. JK flip-flops are often used to build counters. The JK flip-flop will toggle the original output value when triggered by the clock signal if both the J,K inputs are connected with a constant "high"(logic 1). All the JK flip-flops in Figure 2 are negative edge triggered. All the initial values of Q2Q1Q0 are 0. Qo (LSB) (MSB) Input K K Logic 1 Input Q2 000 Figure 2. Counter (a) Sketch the output waveforms forQ2 Q1 Q0. Write down the output binary value (Q2Q1Q0: such as "000", "001") for each clock period on the figure. (b) Describe the function of the counter (e.g. binary down counter counting from 7 to 0).Problem Statement: You design a circuit of a decade counter that will count from 0-9 only. You will only be using the following: (a) Button – only 1 button will be used to trigger the counting. (b) Flip flop IC to used as counting circuit with 4 - BITS binary OUTPUT. (c) IC's for Decoding the Binary OUTPUT of Flip-flops to Decimal Output (d) 7- Segment Display to display the OUTPUT from 0-9. Block Diagram: 4 Bit Binary Flip-Flop 7-Segment Display Button Decoder Circuits Circuitsshow the waveforms for each flip-flop output with respect For the ring counter in Figure to the clock. Assume that FF0 is initially SET and that the rest are RESET. Show at least ten clock pulses. D D. FFO FF1 FF2 FF3 FF4 FF5 FF6 FF7 FF8 FP9 CLK
- Refer to figure 2, carefully, analyze the sequential circuit which contains 2X4 active low decoder decoder, two 2X1 Mux, and JK flip- flop then answer the following questions: what is the state of JK flip-flop if A=0,B=0 and C=1. "note * A: is the most significant bit. C: least significant bit in the state table. **its best for you to draw the state table". 2x1 De FI 2x4 DA Low acti B cnt CIK a. Complement b. Rest c. No change O d. SetDesign a 6-bit counter with control input using flip-flops. Every hour pulseIt should be a design that will increase or decrease by 4 when it arrives. Control input increment orwill determine the decrease. Increasing when control input is 0, decreasing when 1should be designed.Design 1-5 count-up Counters using JK Flip-Flops. 001-010- 011-100- 101- back to 001 03 Required: a) Excitation of Flip-Flop b) State diagram and circuit excitation table. c) Obtain simplified equations using k-map. d) Design logic diagram.
- A 3-bit counter counts in the sequence: 001, 011, 010, 110, 111, 000, 100 and repeats. Draw thelogic diagram for a circuit that implements this. Use D flip-flops. Please explain your process.Design a 3-bit up/down counter using positive edge-triggered T flip-flops. Provide a respective timing diagram to justify the design. Show all the relevant working (state table, state diagram, K-maps, state equations, and final circuit diagram). An up/down counter has two inputs say x, y, and a clock signal. The output should increase by 1 if x = 1 and y = 0 on each rising edge of clock and decrease when x = 0 and y = 1 on each rising edge of clock. When x = y, the output should neither increase nor decrease on each rising edge of clock.Design a 4-bit arithmetic circuit, with two selection variables S1 and S0, that generates the arithmetic operations in the following table. Draw the logic diagram for a single bit stage. Note that B’ represents “Not B”. Draw the logic diagram for a single bit stag
- Design a 4-bit ring counter using D flip-flop and draw the logic diagram of a 4-bit ring counter State Table: 4-bit ring counter (Shift Right) Present Next State State ABCA 001 B 0 101.) A storage register made up of six D flip-flops is storing a binary word. The flip-flop status are: A = set, B = set, C = reset, D = set, E = reset, and F = set. The A flip-flop is the LSB. The decimal equivalent of the register content is 2.) D flip-flops are most frequently used inDesign the 4-bit Johnson Counter using D flip-flop as shown in the figure in the VHDL code. 4 Bit Johnson Counter using D FlipFlop él 9 CLOCK RESET FDC CUR 3 FDC FDC FDC