Answer all parts or leave for someone else to answer. Determine the angle between the axis and the final velocity of A just after the collision, measuredcounterclockwise from the positive z axis.Express your answer using three significant figures.VOAZ IT vec h?Symbols8 =SubmitRequest AnswerDetermine the magnitude of the final velocity of B just after collision.Express your answer to three significant figures and include the appropriate units.OMμÅ?Bitk(VB)2 = ValueUnitsSubmitRequest AnswerDetermine the angle between the axis and the final velocity of B just after the collision, measured clockwisefrom the negative axis.Express your answer using three significant figures.|| ΑΣΦ 11 vecd0₂=Request AnswerSubmit Two smooth disks A and Beach have a mass of 0.5 kg.Both disks are moving with the velocities shown whenthey collide. The coefficient of restitution is e=0.55.Suppose that (A) -7 m/s. (v) 4 m/s.(Figure 1)<10f1Figure(*))Part ADetermine the magnitude of the final velocity of A just after collisionExpress your answer to three significant figures and include the appropriate units.PAm(A)-0.42S

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Answered: Determine the angle between the axis…

Determine the angle between the axis and the final velocity of A just after the collision, measured counterclockwise from the positive z axis. Express your answer using three significant figures.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Part C Determine the magnitude of the final velocity of B just after collision. Express your answer to three significant figures and include the appropriate units. (VB)2 = Value Submit Part D μÅ 02 Submit Request Answer Request Answer www P Units Determine the angle between the x axis and the final velocity of B just after the collision, measured clockwise from the negative x axis. Express your answer using three significant figures. IVE ΑΣΦ ↓↑ vec ? wwwww ? 0
VA₂ PLANE OF CONTACT ÚB₂ X A B 0 m m velocity = 1.52 On an air hockey table, two pucks of identical mass collide in the middle of the rink. Puck A had an initial and puck B had an initial velocity B = 3.1 according to the x-y axis shown. The plane of contact can be thought of as a line angled 0 = 32° above the x-axis. If the coefficient of restitution is e = 0.41 between the pucks, what are the velocities of the pucks after the impact? s i+ i+ m S m Ⓒ 0 UBC Engineering S
A mball = 3 kg cannonball and is shot with an initial velocity of A at an angle 0₁. The cannonball bounces off the ground at point B. The coefficient of restitution between the ball and ground is e = 0.2. Ignore air resistance. Hint: 1. Assume the ground is so large that it will not move. A VA d₁ 0₁ 70 h= Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value VA m S 1.5 m 22 degrees For all velocities, include negatives for direction if appropriate. m a. Determine the y-component of the velocity of the cannonball right before it hits the ground, (VBy) ₁ b. Determine the y-component of the velocity of the cannonball right after it hits the ground, (VBy)ą. c. Determine the max height the cannonball reaches after it hits the ground, h. Round your final answers to 3 significant digits/figures. (VBy)₁ = (VBy)2 = ● m B S m S h
Two smooth disks A and B have the initial velocities shown just before they collide. They have masses m₁ = 6 kg and mB = 3 kg. The coefficient of restitution is e = 0.6. (Figure 1) Figure B A VB = 8 m/s 5. 3 410 VA = 15 m/s Part A Determine the speed of A just after impact. Express your answer to three significant figures and include the appropriate units. ► View Available Hint(s) (VA)2 = Submit Part B _O μА Value www ? Units Determine the speed of B just after impact. Express your answer to three significant figures and include the appropriate units. ► View Available Hint(s) Review
A vehicle of mass 65 tonnes is moving at 85kmph. It collides with a second vehicle of mass 30 tonnes moving in the opposite direction at 40 kmph. After the collision the second vehicle has changed its speed to 2100 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first vehicle after the collision (ii) the coefficient of restitution.
A mball = 3 kg cannonball and is shot with an initial velocity of A at an angle 0₁. The cannonball bounces off the ground at point B. The coefficient of restitution between the ball and ground is e = 0.2. Ignore air resistance. Hint: 1. Assume the ground is so large that it will not move. VA A d₁ d₁ 0₁ h= Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value 70 VA m A s 1.5 m 22 degrees For all velocities, include negatives for direction if appropriate. m a. Determine the y-component of the velocity of the cannonball right before it hits the ground, (VBy)1 b. Determine the y-component of the velocity of the cannonball right after it hits the ground, (VBy) 2. c. Determine the max height the cannonball reaches after it hits the ground, h. Round your final answers to 3 significant digits/figures. (VBy)1 = (VBy)2 = B m S m ●O S
(b) Car 4 is moving with the velocity of 15 m/s when it makes a direct collision with Car B, which is in static condition as shown in Figure 3. The masses of Car A and B are given by m, = 1.6 Mg and mg = 1.5 Mg. The coefficient of restitution between Car A and Car B is e = 0.8. [Kereta A bergerak dengan kelajuan 15 m/s bila ianya menghentam kereta B yang berada dalam keadaan diam seperti dalam Rajah 3. Jisim kereta A dan B adalah m. = 1.6000000000000001 Mg dan ma = 1.5 Mg. Pekali pemulihan di antara kereta A dan B ialah e = 0.8.) (i) Determine the loss of energy due to the collision between both cars. [Tentukan tenaga yang hilang akibat perlanggaran kedua-dua kereta.) (ii) If the loss of energy in (i) need to be increase, suggest suitable parameter that should be change on the system. Justify your answer in calculation. (Jika tenaga yang hilang di (i) ditukar pada system. Justifikasikan jawapan anda dengan pengiraan) ditingkatkan, cadangkar ter bersesuaian yang perlu 15 m/s Car A Car B…
A vehicle of mass 45 tonnes is moving at 85kmph. It collides with a second vehicle of mass 30 tonnes moving in the opposite direction at 50 kmph. After the collision the second vehicle has changed its speed to 2400 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first vehicle after the collision (ii) the coefficient of restitution. 1.The velocity of the first vehicle after the collision in (m/s) is 2.The Coefficient of Restitution is
A truck of mass 50 tonnes is moving at 85kmph. It collides with a second truck of mass 30 tonnes moving in the opposite direction at 60 kmph. After the collision the second truck has changed its speed to 2100 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first truck after the collision (ii) the coefficient of restitution. 1.The velocity of the first truck after the collision in (m/s) is 2.The Coefficient of Restitution is
Two identical hockey pucks moving with initial velocities vA and vg collide as shown. If the coefficient of restitution is e = 0.63, determine the velocity of each puck just after impact. Also calculate the percentage loss n of system kinetic energy. Assume vA = 6.1 m/s, v8 = 12.0 m/s, o = 20°. UA Answers: VA' = ( i i + j) m/s Vg' = ( i i + j) m/s n = i %
There are two bodies which moving towards each other. They collide and stay connected. The presses the spring afterwards. Calculate the spring compression x. Result write in meters. Bodies are assumed as mass points and there is no friction. Bodies remains connected (into one body) after the collision. • m,u4kg • V,=16m/s • m3=Bkg • vz-34m/s • k-3,2kN/m • x+?m; Result needs to be with 3 digits precision k m, m, x=? Answer: 5.657
2 kg move in the directions shown in Figure. Before the and m, has an initial velocity of 8 4 kg and m2 || 3) The masses m¡ collision, the momentum of m, is equal to the momentum of m,, m/s. After the collision, the half of kinetic energy is lost. Find the velocities of the masses m, and m, after the collision. (sin60=0.86 cos60=0.5) Vif y y 60 60 m,}-> x V zi Vii = 8 m/s m, Before the collision v2f After the collision