Determine the mass of each of the two cylinders if they cause a sag of s = 0.5 m when suspended from the rings at A and B. Note that s = 0 when the cylinders are removed. (Draw the free body diagram)
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- i li. In. O MMecnaniCS / مطلوب Untitled Section F1 F2 a F3 B. d F4 F5 Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 = 6 KN; F2 = 7 kN; F3 = 8 KN; F4 = 9 kN; F5 = 10 KN; a = 60°, 0 = 45°, B== 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 74 kN.m c) 88 kN.m d) 59 kN.m e) 241 kN.m 0- 47 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 218.8 kN.m b) – 117.8 kN.m c) - 131.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) - 224.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186.7 kN.m b) - 143.6 kN.m c) 114.6 kN.m d) - 217.9 kN.m e) 224.1 KN.m ) - 135.3 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 217.8 kN.m b) – 139.5 kN.m c) 111.9 kN.m d) 206.9 kN.m e) - 127.1 kN.m f) 99.1 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting f) 321.3 kN.m a) 121.7 kN.m…Situation 4 The truee ia londed se ehown. 60 kN 120 kN 120 kN 120 kN 3m 3m 6m 3m Cnccse the magnitude (kN) ana type (tenaion or ocmpression) cf the foroe in member FE NOTE: Alweye ohocse two (2) anawere but if the member ia zeroforoe member ohoose one (1) anawer only. Seleot the correct reoponoe(o): Teneion 160 100 O 63.25 Compreseion 180 260 60 O 7211 50 56.06 O O O O O O O OComplete solution with free body diagram.
- What is the height h2 (in)? Group B S = 0.7 e = 15 Group A D1 = 6 in S= 0.8 D1 = 5 in D2 = 0.25 in 0 = 10 h1= 2 in D2 = 0.3 in h1= 2.25 in e. Weight of mass = 18 Ibm Weight of mass = 13 lbm Weight- Weight h2 Oil Oil Piston Piston W W. D2 DI D CXQ2/ A belt drive consist of two V-belts in parallel, on grooved pulleys of the size. The angle of the groove is 30°. The cross – section area of each belt is 750 and u is 0.12. The density of the belt material is 1.2 Mg/m' and the maximun stress in the material is 7 MN/m?. Answer the following questions 1- The centrifugal tension in belts is (a) increases power transmitted (b) decreases power transmitted (c) have no effect on power transmitted (d) increases power transmitted up to a certain speed and then decreasesThe 3.1-Mg assembly has a center of mass at G and is hoisted with a constant velocity (Figure 1). Figure 3m 1 m L. 4 m P 4 m B 4 m 1.25 m Determine the force in cable AC. Express your answer to three significant figures and include the appropriate units. Submit FAC= Value Part B ⁰ Submit Part C HÅ 0 Request Answer FAB = Value Determine the force in cable AB. Express your answer to three significant figures and include the appropriate units. H μÅ 4 Request Answer Ű 3 Units C Units ? Determine the distance d for equilibrium. Express your answer to three significant figures and include the appropriate units. Ⓒ P ? ?
- Can you show the free body diagram and the solution?Situation 1: A-D A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi Properties and Dimension Ag=35.30 in^2 rx = 6.24 in ry = 3.74 in d=14.5 in tf=0.94 in bf=14.7 in tw=0.59 in Y k1=1.5 k=1.54 I tf=0.94 d=14.5 tw=0.59 bf=14.7 A. Determine the Yielding Capacity of the section based on LRFD (kips) Round your answer to 2 decimal places. From Situation 1: b. Determine the effective net area of the section. For shear lag Factor U used the recommended values depending on the dimension of the section for W shapes with 3 or more fasteners per line. Note: use hole diameter if bf < d;U=0.85 else U =0.9 3 Round your answer to 3 decimal places. From Situation 1: c. Determine the Tensile Rupture capacity of the section based on LRFD From Situation 1: d. Determine the Demand to Governing Capacity Ratio (based on yielding and rupture only) if the Demand load carried by the…The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontal
- Problem 3-110 ch Two spheres, each 1.3 m in diameter, weigh 5 kN and 13 kN, respectively.. They are connected with a short rope and placed in water. What is the tension in the rope and what portion of the lighter sphere protrudes from the water? Ans: T 1.74 kN; 40.1% RelaThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseQuestion 3) The position of the head and neck and the forces acting on the head are shown in the figure. the center of gravity of the head with a mass of m-9 kg is located at point C. Neck extensor muscles November 21, 2016 by making a y=55° angle with the vertical from point B to the skull, the neck muscle force with a intensity of FmNovember85N is affected. The center of the atlantooccipital joint is located at point B takes. For this flexion position of the head, F, which makes an angle a with the bed from point A, is influenced by the joint response force. (g take the gravitational acceleration as 9.81 m/s2.) According to this; a) Calculate the angle a where the Fjeklem reaction force is built with the horizontal. b) Calculate the Fjeklem reaction force. (Write your result in unit N.) W FM