df=20 confidence interval = 0.90 find out a critical value for left and right tailed test
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df=20
confidence interval = 0.90
find out a critical value for left and right tailed test
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- Confidence Interval for the Difference in Two Population Proportions Neutropenia is an abnormally low number of neutrophils in the blood. Chemotherapy often reduces the number of neutrphils to a level that makes patients susceptible to fever and infections. G. Bucaneve et al. published a study of such cancer patients in the paper "Levofloxacin to Prevent Bacterial Infection in Patients With Cancer and Neutropenia" (New England Journal of Medicine, Vol. 353, No. 10, pp. 977-987). For the study, 375 patients were randomly assigned to receive a daily dose of levofloxacin, and 363 were given a placebo. In the group receiving levofloxacin, fever was present in 243 patients for the duration of neurtropenia, whereas fever was experienced by 308 patients in the placebo group. The 95% confidence interval for the difference in the two proportions is (-.2613, -.1397). Which interpretation is correct? O p1 is substantially smaller than p2, therefore levofloxican is effective in reducing the…Also, find the 95% confidence interval for the mean time required to graduate for all college graduates!What z* (z-critical) would you use if you were making a 66% confidence interval? show on your paper how you are getting your answer
- If a n=30 random sample from a normal population with variance σ^2=2084.49 and a sample mean of 188.1 is taken. construct a 60% confidence interval for the population mean µ construct a 99% confidence interval for the population mean µ what is the best point estimate of the population mean what is the best point estimate of the population varianceIf all other factors are held constant, how does an increase in standard deviation influence the estimated standard error and the width of a confidence interval? O increase the standard error and increase the width increase the standard error and decrease the width decrease the standard error and decrease the width O decrease the standard error and increase the widthA random variable of 7 independent observation of a normal variable gave Ex = 35.9 Ex2 = 186.19 E(x-x)2 = 2.074 Calculate The sample mean The sample variance A 90% confidence interval for the population mean