Diagram for Problems 7-9: 450 AYA 10 m bar weighs 141 N 10 m 450 7. Find the tension of the cable between B and C. Ma cos(45°) = sin(45°) = 0.707 141 N EMA = -141(5)cos(45°) + 10TBC = 0 8. Find the force of A in the direction of the x-axis (A,). EFx = 0: A, - TBC cos(45°) = 0 9. Find the force of A in the direction of the y-axis (A,). EFy = 0: A, + TBC sin(45°) –141=0
Diagram for Problems 7-9: 450 AYA 10 m bar weighs 141 N 10 m 450 7. Find the tension of the cable between B and C. Ma cos(45°) = sin(45°) = 0.707 141 N EMA = -141(5)cos(45°) + 10TBC = 0 8. Find the force of A in the direction of the x-axis (A,). EFx = 0: A, - TBC cos(45°) = 0 9. Find the force of A in the direction of the y-axis (A,). EFy = 0: A, + TBC sin(45°) –141=0
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Diagram for Problems 7-9:
450
AyA
10 m bar weighs 141 N
10 m
B
Ax
450
A
7. Find the tension of the cable between B and C.
A
MA
cos(45°) = sin(45°) = 0.707
141 N
EMA = -141(5)cos(45°) + 10TBC = 0
8. Find the force of A in the direction of the x-axis (A,).
EFx = 0: A - TBC cos(45°) = 0
9. Find the force of A in the direction of the y-axis (A,).
EFy = 0: Ay + TBC sin(45°) –141=0
Transcribed Image Text:4. What is the formula for calculating the power (P) through a resistor, R.
a. P= FR
b. V= IR
c. P= IR?
d. P V/ R?
Diagram for Problems 5-6:
B.
cos(30°) = 0.866
sin(30°) = 0.500
cos(45") = sin(45°) = 0.707
450
A
300
TAB
273 N
5. Find the tension of the cable TAC-
273 N
EFx = 0: -TAB COS(45°) + TẠC cos(30)
EFy = 0: TAB Sin(45º) + TẠC sin(30°) -273- 0
= 0
6. Find the tension of the cable TAB.
TAB = TẠC cos(30°) / cos(45)
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