Q: Identify band in IR Spectra Analysis. Explain it
A: the solution is as follows;
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Q: EXPLAIN INFRARED UNKNOWN. .
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Q: 7000 6000 5000 4000 3000 2000 1000 0- 500 1000 1500 2000 2500 3000 3500
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Q: An absorption spectrum is a graph of ________ or ________ versus ________.
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Discuss interpretation of IR spectrum below.
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Solved in 2 steps
- 2. Use the mass spectrum below to determine a plausible formula for the compound. 100 HS-IU-Os99 80 - 60 40 20 10 20 30 40 50 60 70 80 90 100 110 m/z Relative IntensityA student takes an IR spectrum of an unknown compound. The IR spectrum shows significant stretches at 3159 cm³¹ (m, sh), 3089 cm ¹ (m, sh), 3000 cm ¹ (m, sh), 2997 cm-¹ (m, sh), 1620 cm-¹ (s, sh), 1494 cm-¹ (s, sh), and 1210 cm-¹ (s, sh). Which possible compound is it? Key: S = Strong, M = Medium, W = Weak, Sh = Sharp, Br = Broad Anisole Aniline O Acetanilide O Acetone O PhenolWhat structure is consistent with these spectra? PPM 100 Кey Peaks m/z = 27, 43, 107, 50 109, 150, 152 50 100 150 m/z al Br-
- 8. a) Use the mass spectrum to determine the identity of the halogen atom (X) in the following molecular formula. 100 - C3H5XO2 80- 60 40 20- 152 154 20 40 60 80 100 120 140 160 180 200 m/z Relative Intensity19:25 LTE 1 12D.15 At low resolution, the strongest absorption band in the infrared absorption spectrum of 12C160 is centred at 2150 cm-¹. Upon closer examination at higher resolution, this band is observed to be split into two sets of closely spaced peaks, one on each side of the centre of the spectrum at 2143.26 cm-¹. The separation between the peaks immediately to the right and left of the centre is 7.655 cm¹. Make the harmonic oscillator and rigid rotor approximations and calculate from these data: (a) the vibrational wavenumber of a CO molecule, (b) its molar zero-point vibrational energy, (c) the force constant of the CO bond, (d) the rotational constant B, and (e) the bond length of CO.Give the structure of the molecule that is consistent with each set of spectral data given below: a) C3H6O, 2980, 2860, 1712 cm-1 b) C3H5OCl, 2975, 2864, 1785 cm-1 c) C3H4O, 3070, 2810, 2704, 1705, 1615 cm-1 d) C4H6O2, 3070, 2983, 2846, 1761, 1640 cm-1
- An organic compound having a halogen gives its mass spectrum peaks at m/z 138, 136, 123, 121, 57. The peaks at 138 and 136 are equiaxed and correspond to the molecular ion. The peaks at 123 and 121 are coeval. Identify the type of halogen and how peaks 123, 121, 57 resultExplain why i) the 1'F-NMR spectrum of SF4 consists of two 1:2:1 triplets of equal intensity and ii) the "Se-NMR spectrum of SeF, consist of a triplet of triplets ('Se, I = 77 7714. (a) A compound with molecular formula peak at C12H2408 gave 8 = 3.66 ppm a single (for 'H-NMR) and 8= 70-91 ppm (for 13C). The 13c peak was inverted under DEPT considerations. Predict the molecular structure and assign values.
- explain why C–O stretching occurs at 1100 cm-1 and C=O stretching occurs at 1750 cm-1Draw the structure of the important peaks in the mass spectrum of C9H8O (unsaturation = 6) Major Peaks: m/z = 132, 103, 77, 5312 of 15 The range of IR absorption of C=O stretching vibrations (including ketones, aldehydes, carboxylic acids, esters, acyl halides, anhydrides and amides) is: 2260-2240 cm1 -1 1740-1690 cm" 1650-1550 cm1 1850-1550 cm1