Draw the heating curve (Fully labeling all important features) and calculate the total energy needed in kj to convert 15 g (or 0.83 mol) of water from -40.0 C until fully melted Properties for 4.184 j/gC Solid = 2.09 j/gC Heat of vaporization: water: gas = 1.84 j/gC liquid Hvap = 100.0 C = 40.7 kj/mol Heat of Fusion:4#fus = 6.01 k―ol Freezing Point: 0.0 C Boiling Point: m

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Chapter11: States Of Matter; Liquids And Solids
Section: Chapter Questions
Problem 11.47QP: A quantity of ice at 0C is added to 64.3 g of water in a glass at 55C. After the ice melted, the...
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Draw the heating curve (Fully labeling all important features) and calculate the total energy
needed in kj to convert 15 g (or 0.83 mol) of water from -40.0 C until fully melted Properties for
water: gas = 1.84 j/gC liquid = 4.184 j/gC Solid = 2.09 j/gC Heat of vaporization:
▲Hvap
100.0 C
=
40.7 kj/mol Heat of Fusion:4H fus = 6.01 k―ol Freezing Point: 0.0 C Boiling Point:
m
Transcribed Image Text:Draw the heating curve (Fully labeling all important features) and calculate the total energy needed in kj to convert 15 g (or 0.83 mol) of water from -40.0 C until fully melted Properties for water: gas = 1.84 j/gC liquid = 4.184 j/gC Solid = 2.09 j/gC Heat of vaporization: ▲Hvap 100.0 C = 40.7 kj/mol Heat of Fusion:4H fus = 6.01 k―ol Freezing Point: 0.0 C Boiling Point: m
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