Ethanol (molar mass = 46 g/mol) can be dehydrated to yield ethene (molar mass = 28 g/mol) by heating it with an excess of concentrated sulfuric acid (acting as a catalyst). CH3CH₂OH → CH₂=CH₂ + H₂O If 23.30 g of ethanol produced 12.54 g of ethene, the percentage yield of the product is: (Enter your answer to two significant figures.) %

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Chapter4: Stoichiometry
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Q7 chapter 9: yield calculations Solve asap
Ethanol (molar mass = 46 g/mol) can be dehydrated to yield ethene (molar mass = 28 g/mol) by heating it with an excess of
concentrated sulfuric acid (acting as a catalyst).
CH3CH₂OH → CH₂=CH₂ + H₂O
If 23.30 g of ethanol produced 12.54 g of ethene, the percentage yield of the product is:
(Enter your answer to two significant figures.)
%
Transcribed Image Text:Ethanol (molar mass = 46 g/mol) can be dehydrated to yield ethene (molar mass = 28 g/mol) by heating it with an excess of concentrated sulfuric acid (acting as a catalyst). CH3CH₂OH → CH₂=CH₂ + H₂O If 23.30 g of ethanol produced 12.54 g of ethene, the percentage yield of the product is: (Enter your answer to two significant figures.) %
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