Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g) Part a: Use delta g values =frm a reference to calculate delta g for the reaction. =Delta G = 53 kj/mol Part b: Is this reaction spontaneous under standard conditions at 298k? Delta g is positie, so no. Part c: The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures? (So my question is how do u rearrange the formula ΔG=ΔH-TΔS to solve for the variable ΔS and also what is the answer for part c, i dont understand.
Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g) Part a: Use delta g values =frm a reference to calculate delta g for the reaction. =Delta G = 53 kj/mol Part b: Is this reaction spontaneous under standard conditions at 298k? Delta g is positie, so no. Part c: The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures? (So my question is how do u rearrange the formula ΔG=ΔH-TΔS to solve for the variable ΔS and also what is the answer for part c, i dont understand.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Fe2O3(s) + 3H2(g) = 2Fe(s) + 3H2O(g)
Part a:
Use delta g values =frm a reference to calculate delta g for the reaction.
=Delta G = 53 kj/mol
Part b:
Is this reaction spontaneous under standard conditions at 298k?
Delta g is positie, so no.
Part c:
The value of Delta H for this reaction is 100.kj. At what temperature is this reaction spontaneous at standard conditions? Assume that delta H and delta S do not depend on temperatures?
(So my question is how do u rearrange the formula ΔG=ΔH-TΔS
to solve for the variable ΔS and also what is the answer for part c, i dont understand.
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