Find the forces in members CE and CF in the figure below using the method of sections. Enter your answer in kN, and state whether they are in tension or compressions by using the standard sign convention. Enter the answer for member CE here, and the answer for CF in question 2. 2.4 m 2.4 m 2.4 m A 4 m D F G B. 80 kN 80 kN 80 kN

Find the forces in members CE and CF in the figure below using the method of sections. Enter your answer in kN, and state whether they are in tension or compressions by using the standard sign convention. Enter the answer for member CE here, and the answer for CF in question 2. 2.4 m 2.4 m 2.4 m A 4 m D F G B. 80 kN 80 kN 80 kN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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ENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER 400 N 800 N B D A E C 2 m Use the method of sections to calculate the axial force in members AC and BC. Enter your answer in the following way rounded to the nearest whole number. Example If your answer is TAC 2 N tension TBC =3.1 N compression. enter 2Tension;3Compression Enter TAC then TBC (no space)
In the following armor find the forces in the members CD, KD and JK of section 1-1 indicated in the figure.
The cable carrying three 400-N loads has a sag at C of hC = 14 m. Calculate the following: 26.1 The magnitude of the tensile force in segment AB is Blank 1 N. 26.2 The magnitude of the tensile force in segment BC is Blank 2 N. 26.3 The magnitude of the tensile force in segment CD is Blank 3 N. 26.4 The magnitude of the tensile force in segment DE is Blank 4 N.
RAY F Enter Fpc: Enter Fr The figure above is a pin-joint frame with horizontal member length 1 = 2m and vertical member length h = 4m. (Note that the diagram is not to scale.) You are given that F₁ =45kN, RAY = 15kN and Rpy = 30kN. Use the method of sections to calculate the forces in members BC, FC and FE. Enter your answers in kilonewtons (kN) correct to 2 decimal places. Enter Fac: KN KN F₁ KN RDY
2. Given: Truss with the loads and reactions as shown. Find: The forces in members BD, CD, and CE using the method of sections. Then use a combination of methods to solve for the forces DF and EG Hint: Moments use perpendicular distances. Hint: The sianted forces can be taken as moments about G without resolving into X or Y components to solve for reactions. Methods of joints and sections 1000 N 90 2000 N 90 1000 N 90 130° 90 90 30 12 m 12 m 12 m 1000 N
The truss shown in the figure below is supported on roller at A and a hinge at B. Solve for the | components of reaction. Note: use "m" for distance use "N" for unit of force 600 240 D 16' 12' 12' F 12' BH 400 Ay By MATHalino.com
4.Three members of a frame on a knot plate can be seen in the picture below. Determine the size and direction of the Result of Style on the knot plate analytically and graphically F1 Pelat Buhul F2 F3 F1 = 15 N F2 = 13 N F3 = 10 N Teta = 30 ^o
P1 B D L ft 60° 60 30° 30° E L ft- -L ft- In the figure, L = 10, P1 = 750 lb, and P2 = 620 Ib. Compute the member forces listed below. In each case, tension is positive and compression is negative. [Hint: To find the distance from A to B, you could use the law of sines in triangle ABF. Or, you could first find the distance from C to B in the triangle BCE, which has a right angle at C.]
Q5/A) From the figure below, determine the reaction force at pin C. A 000 0.6 m 10 kN 0.6 m 0.8 m 60° 0.4 m 6 kN OB
with which the bomb hits the target. Question-4 Find the magnitude and nature of the forces in members AC, AD, DB, CE, CF and FD by section method. A 1 kN 2 kN 2 m 2 m H. 2 m 2 m P Type here to search 2]
3-4 Sketch a free-body diagram of each element in the figure. Compute the magnitude and direction of each force using an algebraic or vector method, as specified. F=400 N. 30° B 60° 2 1.9 m 0 9 m C D 60° E x
Determine the forces in all bars of the truss shown in the given figure. Indicate tension or compression. Given: X= 30 kN. BXKN 60 KN The force in member AB (FAB) is The force in member BC (FBC) is The force in member AC (FAC) is [ 6m KN. KN. kN.