Find the time delay for the delay subroutine shown to the right, if the system has an 8051 wit frequency of 11.0592 MHz (C4)
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- The instruction used to fill DX with the its sign bit is: * CWD SAR DX, 1 SAR DX, SF SHR DX, CL SHR DX, SF SAR DX, 10 SAR DX, [SF] SAR DX, 16Write an instruction to sum of the values 9AH, 29H and F4H.Put the sum in registers RO (low byte) and R7 (high byte). (C5) Find the time delay for the delay subroutine shown to the right, if the system has an 8051 with frequency of 11.0592 MHz (C4) DELAY: AGAIN: MOV R2, #150 MOV R3, #250 NOP NOP NOP DJNZ R3, HERE DJNZ R2, AGAIN RETLoad the address 0x12345678 into register $t0 using lui and ori instructions. Write the i-format for these two instructions, given that the opcode for lui is 0x0f and the rs field is unused. Meanwhile, the opcode for ori is 0x0d, the rs and rt fields are both used.
- Q): For the circuit in Figure. write a sequence of instruction to poll switch at 16 of 74F244 that is connected to port 7. Include in the solution the steps required to get the address for the port 7 before writing polling instruction. 0286 UN ACK 19 ALE AD-AD MO DEN RO AD AD- CLK 747373 A3291 leth G 747245 Data but Tarecever bi-drections) DR 18 Ata Au 4 Demultiplexing A₂ A B C 747131 Input Output F₁ Addren decoder 0,0 P₁ Decoder 0-0- CLK 74F374 Cuput Patt DE 74F244 Input Pot Bufer Latch or buffer LED Voc Vbc Input/outputGiven clock = 10MHZ, what is instruction cycle? Please show how to generate 1 second delay. (You can show your idea only or show the codes.)Given the instruction: j Target where its 32-bit format is 0x08100002 and its address in text segment is 0x00400016 Compute the target address (Target) in hexadecimal format
- translate c code in risc-v 32 bit assembly instructions, then convert to machine code(hex) variables a, b, and c are stored in a1, a2, and a3, respectively. Use register a1 for all intermediate values. C code: a=b+c-64; here's what i have so far addi a1,a2,a3 addi a1,a3,-64The "Add immediate unsigned" MIPS instruction: addi Rt, Rs, Imm requires the immediate field to be extended from 16 bits to 32 bits. If the value of the immediate field is: 1111000011110000 what will be the sign extended value of this field from 16 bits to 32 bits? Choose the best answer. 01111111111111111111000011110000 O 11111111111111111111000011110000 O This is a trick question. You cannot sign extend a negative number O 00000000000000001111000011110000 10000000000000001111000011110000 This is a trick question. You cannot sign extend a positive numberFor the instruction 00002480h: beq $s0, $s1, BACKTHERE compute the value of the immediate included in the instructon, given that the target address is FFFFFBE0H O F5D7 O D760 2480 O None of the above
- implement the following equation using arithmetic instruction AX=(((CX+DX)(CX+DX))/CX) , (CX=5 ,DX=5) and store result in A0900 locationd Find the value of the delay in the following program, if the crystal frequency is 11.0592MHz. We suppose each instruction require 2 machine cycles. DELAY: MOV R2,#200 AGAIN: MOV R3,#250 HERE: NOP NOP DJNZ R3,HERE DJNZ R2,AGAIN RETSelect an instruction that tests bit position 8 of register CH. Select the correct response: None of the choices BT CH, 8 TEST CH, 128 a or b