Find two power series solutions of the given differential equation about the ordinary point x = 0: (x2 + 1)y" – 6y = 0.(Please write four terms in first blank and two terms in second one) Y1 = +... and y2 =
Find two power series solutions of the given differential equation about the ordinary point x = 0: (x2 + 1)y" – 6y = 0.(Please write four terms in first blank and two terms in second one) Y1 = +... and y2 =
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 5E
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![Find two power series solutions of the given differential equation about the ordinary point x = 0:
(x2 + 1)y" – 6y = 0.(Please write four terms in first blank and two terms in second one)
Y1 =
+... and y2 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef2b36ca-4a27-4227-a072-bf1ec823a1cc%2F25274d36-7311-4e9f-b2ab-c0c3feb65ab1%2Fmq9k39p_processed.png&w=3840&q=75)
Transcribed Image Text:Find two power series solutions of the given differential equation about the ordinary point x = 0:
(x2 + 1)y" – 6y = 0.(Please write four terms in first blank and two terms in second one)
Y1 =
+... and y2 =
![HWI0 #4 Changed
(x° +a )y" - 7y =0
dist
xy" + Qy" - 7y = o
sort
Ry" + x°y" -Fy = O
Rili-)a; - Fa; =0
j-2 = é
2(;)(j-1) a; +
2(;-2) (j-3)a;-2 - 7aj-z =0
7 -2(j-2)<j-3)
2 (5) (j-1)
%3D
5
R;(j-1)
aj-2
TO(2) - 2(2-5
212)(2-1)
lo(9)-2(4)°-5
%3D
2(4)(4-1)
+ lol6)-2(6)-5
2(6) (6-1)
6
...
= 1 + 1· x
-17
60
...
奇 xe+
35
96
35
152
X° + -
...
13
5760 X
4 80](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef2b36ca-4a27-4227-a072-bf1ec823a1cc%2F25274d36-7311-4e9f-b2ab-c0c3feb65ab1%2F4ud9py_processed.png&w=3840&q=75)
Transcribed Image Text:HWI0 #4 Changed
(x° +a )y" - 7y =0
dist
xy" + Qy" - 7y = o
sort
Ry" + x°y" -Fy = O
Rili-)a; - Fa; =0
j-2 = é
2(;)(j-1) a; +
2(;-2) (j-3)a;-2 - 7aj-z =0
7 -2(j-2)<j-3)
2 (5) (j-1)
%3D
5
R;(j-1)
aj-2
TO(2) - 2(2-5
212)(2-1)
lo(9)-2(4)°-5
%3D
2(4)(4-1)
+ lol6)-2(6)-5
2(6) (6-1)
6
...
= 1 + 1· x
-17
60
...
奇 xe+
35
96
35
152
X° + -
...
13
5760 X
4 80
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