Floretta, a golfer, claims that her drive distance is not equal to 238 meters, a believe her, so she decides to do a hypothesis test, at a 5% significance levell collects the proper data, and works through the testing procedure: HoH=238; H:# # 238 • a = 0.05 (significance level) • The test statistic is X-Ho Zo == a 256-238 V <= 5.6 •The critical values are -20.025-1.96 and 20.025= 1.96. Conclude whether to reject or not reject Ho. and interpret the results. Select the correct answer below: Reject Ho. At the 5% significance level, the test results are not statistically evidence against the null hypothesis. Reject Ho. At the 5% significance level, the data provide sufficient evidenc is not equal to 238 meters. Do not reject Ho. At the 5% significance level, the test results are not stati provide weak evidence against the null hypothesis. Do not reject Ho. At the 5% significance level, the data provide sufficient es distance is not equal to 238 meters.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 11PPS
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Floretta, a golfer, claims that her drive distance is not equal to 238 meters, on average. Several of her friends do not
believe her, so she decides to do a hypothesis test, at a 5% significance level, to persuade them. She hits 19 drives,
collects the proper data, and works through the testing procedure:
• Hou = 238; HH #238
• a = 0.05 (significance level)
The test statistic is
X-Ho
Zo ==
256-238
14
V19
<= 5.6
• The critical values are -20.025 = -1.96 and 20.025 = 1.96.
Conclude whether to reject or not reject Ho. and interpret the results.
Select the correct answer below:
Reject Ho. At the 5% significance level, the test results are not statistically significant and at best, provide weak
evidence against the null hypothesis.
Reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the mean distance
is not equal to 238 meters.
Do not reject Ho. At the 5% significance level, the test results are not statistically significant and at best,
provide weak evidence against the null hypothesis.
Do not reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the mean
distance is not equal to 238 meters.
Transcribed Image Text:Floretta, a golfer, claims that her drive distance is not equal to 238 meters, on average. Several of her friends do not believe her, so she decides to do a hypothesis test, at a 5% significance level, to persuade them. She hits 19 drives, collects the proper data, and works through the testing procedure: • Hou = 238; HH #238 • a = 0.05 (significance level) The test statistic is X-Ho Zo == 256-238 14 V19 <= 5.6 • The critical values are -20.025 = -1.96 and 20.025 = 1.96. Conclude whether to reject or not reject Ho. and interpret the results. Select the correct answer below: Reject Ho. At the 5% significance level, the test results are not statistically significant and at best, provide weak evidence against the null hypothesis. Reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the mean distance is not equal to 238 meters. Do not reject Ho. At the 5% significance level, the test results are not statistically significant and at best, provide weak evidence against the null hypothesis. Do not reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the mean distance is not equal to 238 meters.
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