Answered: For a certain chemical reaction, the…

For a certain chemical reaction, the equilibrium constant K = 2.2 x 10" at 5.00 °C. Calculate the standard Gibbs free energy of reaction. Round your answer to 2 significant digits. | kJ AG° =

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter16: Thermodynamics: Directionality Of Chemical Reactions

Section: Chapter Questions

Problem 105QRT

See similar textbooks

Related questions

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 "C is -60.5 kJ.…

A: Relationship between Gibbs free energy and equilibrium constant is given as: ΔG = ΔG°+ RT ln Q At…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is - 89.9 kJ. Calculate…

A: Given- ΔG=-89.9KJ=-89.9×103J=-89900J K=2.0×1016

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 5.00 °C is 109. kJ.…

Q: What is the value of change in entropy at standard state and 25 degrees Celsius that accompanies the…

A: Recall the given reaction C + CO2 → 2 CO So, change of enropy for this reaction is-…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 139. kJ. Calculate…

Q: Look up the boiling point of benzene. Then calculate the change in Gibbs Free Energy for che…

Q: ST3D.3- At constant temperature and pressure, what is the minimum mass [in g] of glucose needed for…

A: Answer: Value of gibbs free energy change is always equal to non-expansion work and over here…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is – 130. kJ. Calculate…

A: Given: Equilibrium constant, K = 2.6 × 1024 And ΔG0 = -130 KJ = -130000 J.

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 3 B(g) = C(g) + 3 D(g) were…

A: We will. Calculate∆G°

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2 D(g) were…

A: In order to solve this question, we will use law of mass action to find the equilibrium constant at…

Q: The equilibrium constant for the reaction N2(g) + 3 H2(g) ⇌ 2 NH3(g), which corresponds to the…

A: Given reaction and information,

Q: Which one of the following is not equal to zero? A. Standard molar entropy of a perfect crystal…

A: Standard enthalpy of formation of elements and the compounds in their standard state is zero.

Q: At 25 'C, the equilibrium partial pressures for the reaction 3 A(g) +4 B(g) 2 C(g) +2 D(g) were…

A: Equilibrium constant : K = PC2×PD2PA3×PB4 K = 5.672×5.6525.433×4.224 K = 0.0202 Standard Gibb's…

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2 D(g) were…

Q: For the chemical reaction O3(g) + OH(g) → 2 O2(g) + H(g), DrGq = 5.8 kJ/mol at 298 K, 0 J/mol at…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 15.0°C is −143. kJ.…

A: The relationship between standard Gibbs free energy change and equilibrium constant is given by…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is -83.0 kJ. Calculate…

Q: For a certain chemical reaction, the equilibrium constant K=1.6X 10^6 at 20.0°C. Calculate the…

Q: The equilibrium constant for the reaction N2(g) + 3 H2(g) ⇋ 2 NH3(g) is 2.13 × 106 at 288 K and 1.75…

A: The recation is, N2(g) + 3 H2(g) ⇋ 2 NH3(g) The given parametrs are, T1 = 288 K T2 =…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is -104. kJ. Calculate…

Q: For a certain chemical reaction, the equilibrium constant K = 2.8 × 10° at 25.0 °C. Calculate the…

A: Answer:- This question is answered by using the simple concept of calculation od standard Gibbs free…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 83.4 kJ. Calculate…

A: Given that, ∆G°= 83.4 KJ = 83400 J K= 2.4×10-15 T = ?

Q: Consider the (endothermic) thermal decomposition of calcium carbonate: CaCO3(?) → CaO(?) + CO2(?).…

A: Given, Thermal decomposition of calcium carbonate. CaCO3(s)⇌CaO(s)+CO2 (g) It is an example of…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 10.0 °C is 137. kJ.…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is -148. kJ. Calculate…

A: Given that, the standard Gibb's free energy (∆Go) of the reaction - 148 kJ and the equilibrium…

Q: 10 For a certain chemical reaction, the equilibrium constant K = 3.4 × 10º at 30.0 °C. Calculate the…

A: The relationship between standard Gibbs free energy change (∆G°) of reaction and equilibrium…

Q: At 25 °C, the equilibrium partial pressures for the reaction A(g) + 2 B(g) = C(g)+D(g) were found to…

A: Given, A(g) + 2B(g) ⇌ C(g) + D(g) Equilibrium partial pressure for all the above species: PA = 4.22…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is 83.7 kJ. Calculate…

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g)+ 2 D(g) were…

A: The given chemical equilibrium reaction is as follows,3A(g)+2B(g)⇌C(g)+2D(g)Partial pressure of…

Q: For a certain chemical reaction, the equilibrium constant K = 6.2 × 10 10 at 10.0 °C. Calculate the…

A: The relationship between the Gibbs free energy change and equilibrium constant is given by RTln(K)…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is - 147. kJ. Calculate…

A: The relation between standard Gibbs free energy and equilibrium constant is given as: ΔGo= -RT ln…

Q: Calculate the value of the thermodynamic equilibrium constant K.

A: The equilibrium constant can be written as the ratio of concentration of products to the…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0 °C is 116. kJ.…

A: The free energy change of the reaction is = 116. kJ/mol The temperature of the reaction is = 25oC =…

Q: What is the chemical significance of a positive Gibbs free energy change and what is the chemical…

A: The amount of energy available for doing some useful work is termed as free energy or Gibbs free…

Q: Find the value of the equilibrium constant K at 25 °C (298 K) for the reaction 2NH3 (9) + CO, (g) =…

A: The relationship between ΔG0 and equilibrium constant (K) is given by => ΔG0 = -RTln(K) where…

Q: The Gibbs Free Energy Equation: AG change in free energy ΔΗ change in enthalpy TAS (temperature)…

A: Gibbs's free energy measures the spontaneity of the process. The Gibbs free change for a given…

Q: For a certain chemical reaction, the equilibrium constant K = 2.7 x 10¹0 at 5.00 °C. Calculate the…

Q: The chemical reaction that causes aluminum to corrode in air is given by 4Al+3O2→2Al2O3 in which…

Q: Calculate the standard change in Gibbs free energy, AGxn, for the given reaction at 25.0 °C. KCI(s)…

Q: At 25 ∘C25 ∘C, the equilibrium partial pressures for the reaction 3A(g)+4B(g)↽−−⇀2C(g)+3D(g)…

A: The reaction given is 3 A (g) + 4 B (g) ------> 2 C (g) + 3 D (g) Given : equilibrium partial…

Q: At 298 K the equilibrium constant KEo = 6.71 × 10 for the reaction: COCI, (g) CO (g) + CCL (g) а. As…

A: Given: The equilibrium constant, KEQ is 6.71×10-9. COCl2(g)⇌CO(g)+CCl2(g) Equilibrium constant is…

Q: For a certain chemical reaction, the equilibrium constant K = ×7.7106 at 5.00 °C .…

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 3 B(g) = C(g) + 3 D(g) were…

Q: At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 4 B(g) 2C(g) + 2D(g) were…

A: the answer is follows as:

Q: For a certain chemical reaction, the equilibrium constant K 2.2 x 10" at 5.00 °C. Calculate the…

A: Given data contains, The value of equilibrium constant K is 2.2×104. Gas constant R is 8.314…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 10.0 °C is 135. kJ.…

A: The maximum amount of work that is obtained from a thermodynamically closed system is called Gibb's…

Q: a certain chemical reaction, the standard Gibbs free energy of reaction is -133. kJ. Calculate the…

A: Gibbs Free Energy : For a general reaction given below : A + B ⇌ C + D Let;s say the equilibrium…

Q: Standard Gibbs free energy/Gibbs free energy solution Standard Gibbs free energy. Gibbs free energy…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction is – 149. kJ. Calculate…

Question

For a certain chemical reaction, the equilibrium constant K =
2.2 x 10* at 5.00 °C. Calculate the standard Gibbs free energy of reaction.
Round your answer to 2 significant digits.
AG° =
kJ
Check
2021MedrnwHE
Explanation
MacBook Ai

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Calculate the standard Gibbs free-energy change when SO3 forms from SO2 and O2 at 298 K. Why is sulfur trioxide an important substance to study? (Hint: What happens when it combines with water?)
What is the sign of the standard Gibbs free-energy change at low temperatures and at high temperatures for the explosive decomposition of TNT? Use your knowledge of TNT and the chemical equation, particularly the phases, to answer this question. (Thermodynamic data for TNT are not in Appendix G.) 2C7H5N3O6(s) 3N2(g) + 5H2O() + 7C(s) + 7CO(g)
The equilibrium constant for a certain reaction increases by a factor of 6.67 when the temperature is increased from 300.0 K to 350.0 K. Calculate the standard change in enthalpy (H) for this reaction (assuming H is temperature-independent).
What is the sign of the standard Gibbs free-energy change at low temperatures and at high temperatures for the synthesis of ammonia? 3H2(g) + N2(g) 2NH3(g)
Reword the statement in Question 109 so that it is always true. Criticize this statement: Provided it occurs at an appreciable rate, any chemical reaction for which rG 0 will proceed until all reactants have been converted toproducts.
Determine the standard Gibbs free energy change, rG, for the reactions of liquid methanol, of CO(g), and ofethyne, C2H2(g), with oxygen gas to form gaseous carbondioxide and (if hydrogen is present) liquid water at298 K. Use your calculations to decide which of thesesubstances are kinetically stable and which are thermodynamically stable: CH3OH(), CO(g), C2H9(g), CO2(g),H2O().
Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate, is the conversion of fructose6-phosphate to fructose1,6-bisphosphate(bis meanstwo): Fructose6-phosphate(aq) + H2PO4(aq) fructose l,6-bisphosphate(aq) + H2O() + H+(aq) (a) This reaction has a Gibbs free energy change of +16.7 kJ/mol of fructose6-phosphate. Is it endergonic or exergonic? (b) Write the equation for the formation of 1 mol ADP fromATR for which rG = 30.5 kJ/mol. (c) Couple these two reactions to get an exergonic process;write its overall chemical equation, and calculate theGibbs free energy change.
Consider the reaction NH4+(aq) H+(aq)+NH3(aq) Use G f for NH3(aq) at 25C=26.7 kJ/mol and the appropriate tables to calculate (a) G at 25C (b) Ka at 25C
Explain how the entropy of the universe increases when an aluminum metal can is made from aluminum ore. Thefirst step is to extract the ore, which is primarily a formof A12O3, from the ground. After it is purified by freeingit from oxides of silicon and iron, aluminum oxide ischanged to the metal by an input of electrical energy. 2Al2O3(s)electricalenergy4Al(s)+3O2(g)
Use the data in Appendix J to calculate rG andKPat 25 C for the reaction 2HBr(g)+Cl2(g)2HCl(g)+Br2() Comment on the connection between the sign of rG and the magnitude ofKP.
What determines Ssurr for a process? To calculate Ssurr at constant pressure and temperature, we use the following equation: Ssurr = H/T. Why does a minus sign appear in the equation, and why is Ssurr inversely proportional to temperature?
Consider the reaction CO(g)+H2O(g)CO2(g)+H2(g) Use the appropriate tables to calculate (a) G at 552C (b) K at 552C