For all the computed values with decimals, use four (4) digits after the decimal. A wide river that is connected to the proposed Kaliwa Dam was measured using a reciprocal leveling and the foresights and backsights were taken and tabulated below. If the elevation of M is 530.7962 meters, compute the elevation of point N. ASSUME THAT B=0, C=1, D=2, E=1, F=7, G=3

For all the computed values with decimals, use four (4) digits after the decimal. A wide river that is connected to the proposed Kaliwa Dam was measured using a reciprocal leveling and the foresights and backsights were taken and tabulated below. If the elevation of M is 530.7962 meters, compute the elevation of point N. ASSUME THAT B=0, C=1, D=2, E=1, F=7, G=3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Ps i04 kN/2 fzo002 de 0:02 m Find 7
Please answer 11.3 (Answer) 11.1 a. 2995.5kN b. 2358kN c. 2661kN 11.2 a. 726.33kN b. 279.6kN 11.3 793kN
Choices: a. 11624 b. 9115 c. 10273 d. 13221
2.) 30° 20016 TRUSS A 30 30 101 101 5016 30016 SO!VE FORv REACIons
Determine the moment of inertia Ix of the shaded area about the y axis. as the following procedure: 3- find the moment of inertia Ix of the circle part (mm?) |-100 mm-100 mm--150 mm 150 mm 75 mm 150 mm Select one: O 422458309 O 450.06*106 O 24850488.76 O None
Determine the moment of inertia Ix of the shaded area about the y axis. as the following procedure: -100 mm--100 mm--150 mm 150 mm 75 mm 150 mm Select one: O 3659*106 O None O 2559958309 O 1715041691
STATIOΝ DIRECT DOUBLE МEAN REMARKS DEFL. DEFL. DEFL. Azimuth 111 - 112 = 121° 21' R (+) R (+) R (+) 111 147° 01' 293° 59' 112 116° 11' 232° 22' 113 157° 5' 314° 02' 114 59° 2' 119° 8' L (-) ΣAngle Check (Closed Traverse Only): Misclosure by sum of deflection angles: Misclosure by azimuth calculation: (show work for azimuth calculations separately) Note: Add the deflection angles algebraically ( R = + Angle, L = - Angle)
6kN/m 7m 3kN B 2m 5kN/m
Q.1 A line of level is run from B.M.1 (elevation=106.40m) to B.M. 2(elevation=110.50m). The field observations were recorded as given below: Station В.S I.S F.S Remarks 1 1.95 В.М. 1 2 0.65 3 2.60 1.45 4 -1.90 -1.60 5 0.55 6 0.50 В.М. 2 Reduce the level of point 2, 3, 4 and 5, determine the total error of closure, and adjust the values.
(plus sights) BS (+) Station HI BMA 6.87' 1031.19' TP1 4.98' TP2 7.43' TP3 0.98' TP4 4.57' TP5 8.20' трь 3.65' TBMX 8.52' TP7 2.22' TP8 7.04' TP9 4.74' TPID 3.68' ΤΡΙ 5.90' BMA Σ = (minus sights) (minus sights) FS (-) IFS (-) 5.32' 6.27' 2.84' 8.34' 3.76 6.52' 5.97' 5.89¹ 4.63' 2.39' 6.00⁰ 8.27 2.60' Check: Misclosure: Permissible Misclosure: Adjustment: Elevation 1024.32 102398 Published Information for BM 303- elevation = 1024.32' (NAVD88) Fieldnote information: BS on BM 303 = 6.87' FS on TP1= 5.32' BS on TP1 = 4.98' FS on TP2 = 6.27' BS on TP2= 7.43' FS on TP3= 2.84' BS on TP3= 0.98' FS on TP4 = 8.34' BS on TP4 = 4.57' FS on TP5= 3.76' BS on TP5= 8.20' FS on TP6= 6.52' BS on Tp6= 3.65' FS on TBM R22 = 5.97' BS on TBM R22 = 8.52' FS on TP7 5.89' BS on TP7= 2.22' FS on TP8= 4.63' BS on TP8 7.04' FS on TP9 = 2.39' BS on TP9 = 4.74' FS on TP10= 6.00' BS on TP10 = 3.68' FS on TP11 = 8.27' BS on TP11= 5.90' FS on BM 303 = 2.60'
The pin-jointed space truss shown in Fig. P.15.14 is pinned to supports 0, 4, 5 and 9 and is loaded by a force P in the x direction and a force 3P in the negative y direction at the point 7. Find the rotation of the member 27 about the z axis due to this loading. All members have the same cross-sectional area, A, and Young's modulus, E. (Hint. Calculate the deflections in the x direction of joints 2 and 7.) Ans. 382P19AE.
3.44 Solve for CD, HD, and HG. A 60° B 10! I C 10¹ K H 2K 10' 6 E 4K ALBERTON 10¹ TU F