h= 6.626x1034 J.s c=2.998x10% m.s1 1 eV = 1.6022x10-19 J 1Å = 10-10 m,%3Dx*e-ax² dx = O" sin e de =1/2S" sin50616mẹ =9.109x10-31 kg, k= 1.3807x10-23 J/K8a215 For 'H³°CI molecule, (N1/No) ratio at 300 K is 6.091 x 10² . Calculate thewavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

We know for rotational transition, EJ= BJ(J+1) cm-1 ; where B is rotational constant. From this…

Answered: For 'H³C1 molecule, (N¡/No) ratio at…

For 'H³C1 molecule, (N¡/No) ratio at 300 K is 6.091 x 10² . Calculate the wavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter15: Introduction To Electronic Spectroscopy And Structure

Section: Chapter Questions

Problem 15.60E

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Question

h= 6.626x1034 J.s c=2.998x10% m.s1 1 eV = 1.6022x10-19 J 1Å = 10-10 m,
%3D
x*e-ax² dx = O" sin e de =
1/2
S" sin50
6
16
mẹ =9.109x10-31 kg, k= 1.3807x10-23 J/K
8a2
15

For 'H³°CI molecule, (N1/No) ratio at 300 K is 6.091 x 10² . Calculate the
wavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

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