For the 0.5 M Acetic Acid Solution: Chemicals CH3COOH(aq) CH3COO(aq) H3O* (ag) K₁ Calculation: I(initial) 0.5 0 0 C(change) -.0095 +.0095 +.0095 E(equilibrium) (0.5-x) X X

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter16: Thermodynamics
Section: Chapter Questions
Problem 58E: Given that the Gf for Pb2+(aq) and Cl-(aq) is -24.3 kJ/mole and -131.2 kJ/mole respectively,...
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For the 0.5 M Acetic Acid Solution:
Chemicals
CH3COOH(aq)
CH3COO(aq)
H3O* (ag)
K, Calculation:
I(initial)
0.5
0
0
Average K₂ of both solutions:
Part II-Sodium Acetate
pH
[OH Jeq
C(change)
-.0095
+.0095
+.0095
0.3 M
9.11
1.29 x 10^5
E(equilibrium)
(0.5-x)
X
X
0.5 M
9.21
Transcribed Image Text:For the 0.5 M Acetic Acid Solution: Chemicals CH3COOH(aq) CH3COO(aq) H3O* (ag) K, Calculation: I(initial) 0.5 0 0 Average K₂ of both solutions: Part II-Sodium Acetate pH [OH Jeq C(change) -.0095 +.0095 +.0095 0.3 M 9.11 1.29 x 10^5 E(equilibrium) (0.5-x) X X 0.5 M 9.21
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