For the circuit shown below, € = 17V, L = 8mH, and R = 50. After steady state is reached with S₁ closed and S₂ open, at t = 0, S₂ is closed and S₁ is opened. Determine (a) the current through L at t = 0, (b) the current through L at t = 4 × 10-¹s, (c) the voltage across R on the right at t = 4 × 10–¹s, and (d) the rate at which current through L changes at t = 4 × 10—¹s. The current through L at t = 0 is 3.4 A. The current through L at t = 4 x 10-4s is 2.6479 A. The voltage across R at t = 4 x 10-48 is 13.2395 V The rate at which current through L changes at t = 4 × 10-¹s is -470.0625 R www S₁ 0000 www A/s

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter29: Direct Current (dc) Circuits
Section: Chapter Questions
Problem 72PQ: A capacitor with initial charge Q0 is connected across a resistor R at time t = 0. The separation...
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How is "The rate at which current through L changes at t = 4*10^-4 s" solved for?

For the circuit shown below, € = 17V, L = 8mH, and R = 50. After steady state is reached with S₁ closed and S₂
open, at t = 0, S₂ is closed and S₁ is opened. Determine
(a) the current through L at t = 0,
(b) the current through L at t = 4 × 10-¹s,
(c) the voltage across R on the right at t = 4 × 10–¹s, and
(d) the rate at which current through L changes at t = 4 × 10—¹s.
The current through L at t = 0 is 3.4
A.
The current through L at t = 4 x 10-4s is 2.6479
A.
The voltage across R at t = 4 x 10-48 is 13.2395 V
The rate at which current through L changes at t = 4 × 10-¹s is -470.0625
R
www
S₁
0000
www
A/s
Transcribed Image Text:For the circuit shown below, € = 17V, L = 8mH, and R = 50. After steady state is reached with S₁ closed and S₂ open, at t = 0, S₂ is closed and S₁ is opened. Determine (a) the current through L at t = 0, (b) the current through L at t = 4 × 10-¹s, (c) the voltage across R on the right at t = 4 × 10–¹s, and (d) the rate at which current through L changes at t = 4 × 10—¹s. The current through L at t = 0 is 3.4 A. The current through L at t = 4 x 10-4s is 2.6479 A. The voltage across R at t = 4 x 10-48 is 13.2395 V The rate at which current through L changes at t = 4 × 10-¹s is -470.0625 R www S₁ 0000 www A/s
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