for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. #1 = 372nm, 2 = 370, nm 3 = 370nm, 4 =372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can you correct it and give the 95% confidence interval for a sample. Report table 2: Determination of Molar absorptivity of K2CrO4 ppm of K:CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012 Molarity of K CrO₁ in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3 Peak wavelength Peak Absorbance From spectrum max=372 nm A=0.487 8= 1 2 3 A=0.434 A=0.487 A=0.347 From single wavelength values A=0.370 8= === 1.2864×10 6 1.5171×10^6 εm Ɛm 1.7023×10^6 1.20642×10^6 Average & (for the 4 readings) Standard deviation of ε 95% Confidence interval of E = 1.428055×10^6 =2 = Show sample calculation (for solution 1): = A/b.c = Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter16: An Introduction To Infrared Spectrometry
Section: Chapter Questions
Problem 16.14QAP
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for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. # 1 = 372nm, 2 = 370, nm
3 = 370nm, 4 = 372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can you
correct it and give the 95% confidence interval for a sample.
د
Report table 2: Determination of Molar absorptivity of K2CrO4
ppm of K2CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012
Molarity of K CrO in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3
Peak wavelength
Peak Absorbance
From spectrum
max=372 nm
A=0.487
8=>
1
2
3
4
A= 0.370
A=0.434
A=0.487
A= 0.347
From single
wavelength
values
=
8=
1.2864×10^6
1.5171×10^6
1.7023×10 6 1.20642×10^6
Average & (for the 4
readings)
Standard deviation of
95% Confidence interval
of €
=1.428055×10^6
=2
Show sample calculation (for solution 1): 2= A/b.c =
Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1
Transcribed Image Text:for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. # 1 = 372nm, 2 = 370, nm 3 = 370nm, 4 = 372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can you correct it and give the 95% confidence interval for a sample. د Report table 2: Determination of Molar absorptivity of K2CrO4 ppm of K2CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012 Molarity of K CrO in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3 Peak wavelength Peak Absorbance From spectrum max=372 nm A=0.487 8=> 1 2 3 4 A= 0.370 A=0.434 A=0.487 A= 0.347 From single wavelength values = 8= 1.2864×10^6 1.5171×10^6 1.7023×10 6 1.20642×10^6 Average & (for the 4 readings) Standard deviation of 95% Confidence interval of € =1.428055×10^6 =2 Show sample calculation (for solution 1): 2= A/b.c = Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1
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