For the reaction shown below, 2.00 g of 4- chloroacetophenone, 10.0 mol of sodium broohydride, 3 equivalents of acetic anhydride (Ac₂O), 2 equivalents of triethylamine (TEA), and 1.0 mmol of DMAP are used to obtain 1.80 g of the desired product, 1-(4-chlorophenyl)ethyl acetate. What is the percent yield of the desired product? 4-chloroacetophenone 154.59 g/mol O 78.06% 79.08% O 77.4% 56.29% O 70.25% NaBH DCM:MOH OH 1-44-chlorophenylethanol 156.61 g/mol Ac₂0 TEA DMAP DCM Desired Product 198.04 g/mol

For the reaction shown below, 2.00 g of 4- chloroacetophenone, 10.0 mol of sodium broohydride, 3 equivalents of acetic anhydride (Ac₂O), 2 equivalents of triethylamine (TEA), and 1.0 mmol of DMAP are used to obtain 1.80 g of the desired product, 1-(4-chlorophenyl)ethyl acetate. What is the percent yield of the desired product? 4-chloroacetophenone 154.59 g/mol O 78.06% 79.08% O 77.4% 56.29% O 70.25% NaBH DCM:MOH OH 1-44-chlorophenylethanol 156.61 g/mol Ac₂0 TEA DMAP DCM Desired Product 198.04 g/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

In preparation of p-Nitroaniline, Starting material is 50g of p-nitroacetanilide, 22ml of HCI, 20g of p-nitroaniline. Give % yield of nitro acetanilide.
Specialized reagents and their acronyms: MCPBA= meta-chloroperbenzoic acid; HOAC = acetic acid, NaOAc = Sodium Acetate; Ph= phenyl = C6H5-; P(Ph)3 = triphenyl phosphine; NBS = N- bromosuccinimide, PBR3, SOCI2, AlCl3, FeBr3, H2SO4, Li, Na, Mg, Br2, CrO3, LDA = lithium diisopropylamide, PCC = pyridinium chlorochromate, KO-C(CH3)3, LAH = LIAIH4, (sia)2BH = disecondary isobutyl borane, KMNO4, HIO4 = periodic acid %3D %3D %3D %3D %3D write the missing reagents and solvents over the arrows. Some transformation require multiple steps. In some cases there will be multiple arrows. Br Br
Specialized reagents and their acronyms: MCPBA= meta-chloroperbenzoic acid; HOAC = acetic acid, NaOAc = Sodium Acetate; Ph= phenyl = C6H5-; P(Ph)3 = triphenyl phosphine; NBS = N- bromosuccinimide, PBR3, SOCI2, AICI3, FeBr3, H2SO4, Li, Na, Mg, Br2, CrO3, LDA = lithium diisopropylamide, PCC = pyridinium chlorochromate, KO-C(CH3)3, LAH = LIAIH4, (sia)2BH = disecondary isobutyl borane, KMNO4, HIO4 = periodic acid %3D write the missing reagents and solvents over the arrows. Some transformation require multiple steps. In some cases there will be multiple arrows. Ph -Ph Ph Ph Br
Specialized reagents and their acronyms: MCPBA= meta-chloroperbenzoic acid; HOAC = acetic acid, NaOAc = Sodium Acetate; Ph= phenyl = C6H5-; P(Ph)3 = triphenyl phosphine; NBS = N- bromosuccinimide, PBR3, SOCI2, AICI3, FeBr3, H2SO4, Li, Na, Mg, Br2, CrO3, LDA = lithium diisopropylamide, PCC = pyridinium chlorochromate, KO-C(CH3)3, LAH = LIAIH4, (sia)2BH = disecondary isobutyl borane, KMNO4, HIO4 = periodic acid %3D %3D %3D %3D %3D %3D %3D write the missing reagents and solvents over the arrows. Some transformation require multiple steps. In some cases there will be multiple arrows. ОН H. (R) Br (S) HO OH
Specialized reagents and their acronyms: MCPBA= meta-chloroperbenzoic acid; HOAC = acetic acid, NaOAc = Sodium Acetate; Ph= phenyl = C6H5-; P(Ph)3 = triphenyl phosphine; NBS = N- bromosuccinimide, PBr3, SOCI2, AICI3, FeBr3, H2SO4, Li, Na, Mg, Br2, CrO3, LDA = lithium diisopropylamide, PCC = pyridinium chlorochromate, KO-C(CH3)3, LAH = LIAIH4, (sia)2BH = disecondary isobutyl borane, KMNO4, HIO4 = periodic acid %3D %3D %3D %3D %3D write the missing reagents and solvents over the arrows. Some transformation require multiple steps. In some cases there will be multiple arrows. Ph CH CH o 0om ilubongo CEC-Ph In questions 14-24, write the products of the following transformations. If there is no reaction write NR. Indicate R or S or racemic or indicate cis or trans where appropriate OH + LDA THF solvent (S) Ph
For the reaction shown below, 582 mg of 4-chlorophenol, 798 mg of benzyl bromide, and excess sodium hydroxide are used to obtain 847 mg of 4-chlorophenyl benzyl ether. What is the percent yield of 4-chlorophenyl benzyl ether? 4-chlorophenol MW = 129 g/mol; benzyl bromide MW = 171 g/mol; sodium hydroxide MW = 40.0 g/mol; 4-chlorophenyl benzyl ether MW = 219 g/mol
Write an equation for the acid-base reaction between 2,4-pentanedione and sodium eth- oxide and calculate its equilibrium constant, K. The pK, of 2,4-pentanedione is 9; that of ethanol is 15.9. CH,CCHÖCH, + CH,CH,O Na* H 2,4-Pentanedione Sodium ethoxide
What is the theoretical yield and limiting reagent for the reaction of benzophenone with sodium borohydride to form diphenyl methanol as described in the experiment provided if you begin with 1.75g of benzophenone in 25 mL of 95% ethanol and add 0.75 g of sodium borohydride portion wise over 45 minutes?
1015MSC Chemistry of Biological Systems II 2021 2. What kind of results do you expect to see when the following compounds are mixed together with the given test solution? Indicate positive or negative in the table below. (a) with 2,4-dinitrophenylhydrazine (b) with Benedict's reagent (c) with lodoform reagent CH3 (d) with Tollen's reagent
A wittig reaction experiment: Week 1 -》 preparation of phosphonium salt Materials : triphenylphosphine (5.3g),methyl Bromoacetate 3.36g (2.1ml) , ethanol 30ml . The yield obtained was 8.93g . Calculate the percentage yield Week 2 -》 Formation of the tlide and wittig reaction Materials :Phosphonium salt (5g), napthyl-2- carboxwaldehyde( 2.65g), 20 ml of water and 5 nl of Nahco3. Yield obtained was 0.51g .Calculate the percentage yield Week 3: Solvent free wittig reaction Materials: Benzyltriphenylphosphonium chloride (0.5g ), 4 - Bromoabenzaldehyde (0.24g), Potassium phosphate (tribasi c) 0.275g .The yield obtained was 1.21g. Calculate the percentage yield
(a) calculate the theoretical yield, in grams, of trans-9-(2-phenylethenyl) anthracene. (b) Calculate the percent yield Data for the Synthesis of trans-9-(2-phenylethenyl)-anthracene: A Wittig Reaction Mass of filter paper: 0.688 g Mass of filter paper with product: 1.113 g Melting Point of Product: 129-130oC
Pls solve this question correctly in 5 min i will give u like for sure Balance the chemical equation of a reaction formed by the bromination of trans-cinnamic acid if we started with 0.3088 grams of trans cinnamic acid and 1mL of bromine. The product of this reaction is 2,3 - dibromo - 3- phenylpropanoic acid