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- Mass spectrometry of chlorine from an asteroid sample shown. Intensity 34 35 36 37 38 Mass mu What is the relative abundance of 35C1 in this sample? 57.1% 42.9% 52.8%What is in a fractionating column? Silica gel Collected fractions Glass or plastic beads Liquid nitrogenally. * Question Completion Status: QUESTION 1 During the experiment, the mass of original sample of compound was 2.965 g, and the mass of copper obtained was 1.006 g. Based on these numbers, calculate the mass of chlorine in the original sample in grams. Include the unit and three decimal places in your answer. QUESTION 2 6. If 1.045 g of copper was obtained in the experiment, how many moles (mol) of copper is this? Include the unit and five decimal places in your answer. QUESTION 3 During the experiment, a student calculated the mass of chlorine in the compound to be 1.186 g. How many moles (mol) of chlorine are in the Save All Answers Click Save and Submit to save and submit. Click Save All Answers to save all answers. DELL II
- Sample Physical Appearance 0.1 M Na2CO3 0.1 M CaCl2 Na2CO3 + CaCl2 mixture Part II filtrate + CaCl2Page 2 2. A 0.9527 g sample containing only KCI and CaCl2 yielded 3.9802 g of dried Hg2Cl2. Calculate the percent of each halogen compound in the sample. KCI = K* + CIr; CaCl2 = Ca2+ + 2C-; 2CI- + 2Hg* = Hg2Cl2 CI 35.453; K 39.0983; Ca 40.078; Hg 200.59The amount of ascorbic acid in cashew juice of different brands was determined by two different methods, colorimetry and titrometry. The results obtained for the two methods for analyzing the different cashew juice are necessary in the following table. Sample Colorimetry (mg/100g) Titrometry (mg/100g) juice brand A 152,2 153,7 juice brand B 150,7 150,7 juice brand C 18,7 18,7 juice brand D 67,4 67,4 Can the two methods be used, indistinctly, to determine ascorbic acid in cashew juice, at a 95% confidence level? Explain.
- student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…If the plant poduces 1.6*10- kg(1600 metric ton) of Cl2 daily, estimate the quanties of H2 produced 2NaCl(aq) + 2H2O(l)--> 2NaOH(aq) + H2 (g) + Cl2 (g)Potentially Useful Information Spectrochemical Series: | < Br < SCN¯ < Cl° < NO3¯ < F° < OH° < C2O4²¯ ~ H2O < NCS° < NH3 < en < PPH3 く A student has three test tubes containing a metal (M) nitrate solution M(NO3)2 (aq) (where "M" represents a generic transition metal). The student adds aqueous ammonia (NH3) to one test tube, aqueous hydrochloric acid (HCI) to the second tube, and nothing more to the third tube, but forgets to label the tubes. After this, one test tube contains a red solution, one an orange solution, and one a yellow solution. Note: This metal, M, would follow the same rules that we used for Cu(II), Ni(II), and Co(II). The Jahn-Teller Effect does not apply. Complete each statement or answer each question below about the solutions in the three test tubes. The aqua complex causes less splitting of the d orbitals of the metal than the... ammonia complex. O chloro complex.
- ksp CaCO3 3.36×10-9 Ca(OH)2 5.02×10-6Potentially Useful Information Spectrochemical Series: I < Br < SCN < Cl° < NO3¯ < F° < OH° < C2O4² ~ H2O < NCS" < NH3 < en < PPH3 A student has three test tubes containing a metal (M) nitrate solution M(NO3)2 (aq) (where "M" represents a generic transition metal). The student adds aqueous ammonia (NH3) to one test tube, aqueous hydrochloric acid (HCI) to the second tube, and nothing more to the third tube, but forgets to label the tubes. After this, one test tube contains a red solution, one an orange solution, and one a yellow solution. Note: This metal, M, would follow the same rules that we used for Cu(II), Ni(II), and Co(II). The Jahn-Teller Effect does not apply. Complete each statement or answer each question below about the solutions in the three test tubes. The red solution contains a coordination complex with... O ammonia (NH3) as the ligand. chloride ion (CI') as the ligand. nitrate ion (N03°) as the ligand. water (H20) as the ligand.A sample of anhydrous NaHCO3 (FM = 84.007) is suspected to be contaminated with eitherNaOH (FM = 39.997) or Na2CO3 (FM = 105.989). To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using double flask method. If the sample requires 0.45 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and 35.95 mL to reach the bromcresol green endpoint, calculate the percentage composition (in %w/w) of all the basic components in the sample.